You can use prime factorization to find the GCF of a set of numbers. This often works better for large numbers, where generating lists of all factors can be time-consuming.
Here’s how to find the GCF of a set of numbers using prime factorization:
* List the prime factors of each number.
* Circle every common prime factor — that is, every prime factor that’s a factor of every number in the set.
* Multiply all the circled numbers.
The result is the GCF.
For example, suppose you want to find the GCF of 28, 42, and 70. Step 1 says to list the prime factors of each number. Step 2 says to circle every prime factor that’s common to all three numbers (as shown in the following figure).
As you can see, the numbers 2 and 7 are common factors of all three numbers. Multiply these circled numbers together:
2 · 7 = 14
Thus, the GCF of 28, 42, and 70 is 14.
The answer is
9n-2
d=9
1#=7
Answer: 824$ for each
and will have to discount 24$ for each ticket
Step-by-step explanation: 2472/3= 824
2400/3=800
824-800=24
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now
2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4
At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real.
Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result.
For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196
No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.
So x^2 = -4 has no real solutions. Taking the square root of both sides leads to
x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values