Answer:
607 students to guarantee that there are two students with the same professorwho earned the same final examination score.
Step-by-step explanation:
This problem is an example of the Pigenhole principle.
The first step is finding the number of boxes and objects:
For each score, we have a box which contains the student who got that score.
If there were only one professor grading, there would need to be 101+1 = 102 students to ensure that that there are two students with the same professorwho earned the same final examination score.
However, for each student, there are a combination of six to five = 6 possible combinations for a score.
So there should be at least 6*101+1 = 607 students to guarantee that there are two students with the same professorwho earned the same final examination score.