What is the domain and range of this map?

There are two unknowns you are trying to find, and you cannot express one in terms of the other. Describe how you could use alge

serious [3.7K]

Answer:

When you solve systems with two variables and therefore two equations, the ... of any variable is 1, which means you can easily solve for it in terms of the other ... In the substitution method, you use one equation to solve for one variable and ... Look for a variable with a coefficient of 1 … that's how you'll know where to begin.

Step-by-step explanation:

4 0

3 years ago

WILL MARK BRAINLIEST!!! 40 POINTS!! ACTUAL ANSWERS, PLZZZ

vitfil [10]

Answer:

Step-by-step explanation:

PART A: 2x^5 + 3x^2-3

It is a fifth degree polynomial because, the highest degree is 5 and it is in the standard form since, the polynomial is written in descending order i.e, from highest degree to the least

part B:

Closure property is applicable to the subtraction of polynomials.

for example 2x^4+2x^2-5 is a polynomial and 2x^3+2x+2 is also a polynomial.

if we subtract these two polynomials, the outcome

2x^4-2x^3+2x^2-2x-7 is also a polynomial

4 0

3 years ago

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A small theater had 7 rows of 23 charis workers just removed 9 of these chairs

pshichka [43]

Answer:

152 Chairs

Explanation:

7 rows of 23 chairs: 7 · 23

7 · 23 = 161

Remove 9

161 - 9 = 152

6 0

3 years ago

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The resting heart rate for an adult horse should average about µ = 47 beats per minute with a (95% of data) range from 19 to 75

KatRina [158]

Answer:

a. 0.0582 = 5.82% probability that the heart rate is less than 25 beats per minute.

b. 0.1762 = 17.62% probability that the heart rate is greater than 60 beats per minute.

c. 0.7656 = 76.56% probability that the heart rate is between 25 and 60 beats per minute

Step-by-step explanation:

Empirical Rule:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean:

$\mu = 47$

(95% of data) range from 19 to 75 beats per minute.

This means that between 19 and 75, by the Empirical Rule, there are 4 standard deviations. So

$4\sigma = 75 - 19$

$4\sigma = 56$

$\sigma = \frac{56}{4} = 14$

a. What is the probability that the heart rate is less than 25 beats per minute?

This is the p-value of Z when X = 25. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{25 - 47}{14}$

$Z = -1.57$

$Z = -1.57$ has a p-value of 0.0582.

0.0582 = 5.82% probability that the heart rate is less than 25 beats per minute.

b. What is the probability that the heart rate is greater than 60 beats per minute?

This is 1 subtracted by the p-value of Z when X = 60. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60 - 47}{14}$

$Z = 0.93$

$Z = 0.93$ has a p-value of 0.8238.

1 - 0.8238 = 0.1762

0.1762 = 17.62% probability that the heart rate is greater than 60 beats per minute.

c. What is the probability that the heart rate is between 25 and 60 beats per minute?

This is the p-value of Z when X = 60 subtracted by the p-value of Z when X = 25. From the previous two items, we have these two p-values. So

0.8238 - 0.0582 = 0.7656

0.7656 = 76.56% probability that the heart rate is between 25 and 60 beats per minute

3 0

3 years ago

Given a set of data sorted from smallest to largest, define the first, second, and third quartiles.

Nikolay [14]

Answer:

Step-by-step explanation:

Given a set of data sorted from smallest to largest, i.e. arranged in ascending order we are to find out the median, I and III quartiles

We know that the median is the middle entry of data arranged in ascending order

Q1 is the entry below which 25% lie and Q3 is one above which 25% lie

Hence proper definition would be

d. The first quartile is the median of the lower half of the data below the overall median.

The second quartile is the overall median

The third quartile is the median of the upper half of the data above the overall median.

Option b is wrong becuase mean is not necessary here. Option a is wrong because this has nothing to do with std deviation

Option c is wrong since minimum value cannot be q1

Option e is wrong because we have exactly 25% lie below Q1

4 0

3 years ago