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NeTakaya
4 years ago
15

The table below shows some characteristics of three different types of muscles. Characteristics of Different Types of Muscles Ty

pe A Muscles Type B Muscles Type C Muscles Striations Yes Yes No Found in digestive and urinary system No No Yes Found in musculoskeletal system Yes No No Which type of muscle is Type B? Cite the evidence from the chart to support your answer.
Type B are skeletal muscles, because only skeletal muscles have striations.

Type B are cardiac muscles, because they are not found in any other part of the body.

Type B are skeletal muscles, because they are not part of the digestive system.

Type B are cardiac muscles, because they do not tire easily.
Biology
1 answer:
Assoli18 [71]4 years ago
5 0

Answer:

Type B are cardiac muscles, because they are not found in any other part of the body.

Explanation:

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The question is incomplete. Here is the complete question.

You are studying a population of ground squirrels. You trap 100 individuals and find 9 that have a light colored coat and the rest have a dark coat. You know that light coat color is recessive in ground squirrels. What is the allele frequency for the light coat allele  and the dark coat allele? How many of the dark coated individuals do you expect to be heterozygotes at the coat color gene? Assume the population is at H-W equilibrium.

Answer: Allele frequency for light coat: q = 0.3;

              Allele frequency for dark coat: p = 0.7;

             There will be 42 heterozygote;

Explanation: A population in H-W equilibrium is a population which doesn't change from one generation to the next if there are no disturbing factors, as migration or mutation.

It follows the equation: p^{2}+2pq+q^{2}=1.

p represents the frequency of the dominant allele;

q represents the frequency of the recessive allele;

2pq represents heterozygote individuals;

The sum of frequencies of both alleles must be 1, i.e.: p+q=1

For the population of squirrels:

  • Frequency of recessive allele

q^{2} = \frac{9}{100}

q = \sqrt{\frac{9}{100}}

q = 0.3

  • Frequency of dominant allele

p+q=1

p=1-q

p=1-0.3

p = 0.7

  • Frequency of heterozygote

2pq = 2*0.7*0.3 = 0.42

In a population of 100 individuals: 0.42*100 = 42

The allele frequency for the light coat is 0.3; for the dark coat is 0.7.

It is expected to have 42 heterozygote individuals in this population.

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