Question

A single number is chosen from the digits 1 through 30. Find the probability that the number is an even number or a number divisible by 3.

Answer 1

Answer:

There is a 66.67% probability that the number is an even number or a number divisible by 3.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Desired outcomes:

These are the following even numbers from 1 through 30: 2,4,6,8,10,12,14,16,18,20,22,24,26,28,30

There are 15 even numbers.

These are the following numbers divisible by 3 from 1 through 30:

3,6,9,12,15,18,21,24,27,30

We only count the odd numbers here, since we have already counted the even ones.

There are 5 odd numbers divisible by 3.

So there are 20 numbers that are even numbers or divisible by 3. So there are 20 desired outcomes.

Total outcomes:

There are 30 numbers from 1 through 30. So the number of total outcomes is 30.

Find the probability that the number is an even number or a number divisible by 3.

$P = \frac{2}{3} = 0.6667$

There is a 66.67% probability that the number is an even number or a number divisible by 3.