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DaniilM [7]
2 years ago
15

HELP QUICK!! IL MARK YOU BRAINLIEST

Mathematics
2 answers:
Anastasy [175]2 years ago
8 0

Answer:

Step-by-step explanation:

Systems of measurement are defined because we all need to use the same measurements. For example, if we said something is 2 "feet" long, then a person with big feet would make it longer than someone with small feet.

Law Incorporation [45]2 years ago
6 0

Answer:

  to support commerce

Step-by-step explanation:

Units of length, mass (weight), and time are defined as national and international standards in order to support commerce.

When you go to purchase a given length of material, you can only do that if your unit of length is the same as the merchant's unit of length.

The same is true for a mass of material. You can only be assured of obtaining 10 pounds of apples, if your pound is the same as the merchant's pound.

If you contract your time at some rate per hour, you and your employer will only be satisfied if your time units are the same.

That is, standard units of length, mass, and time are required for orderly conduct of business.

__

<em>Additional comment</em>

The SI system of units defines the meter, kilogram, and second using specific numbers of wavelengths of light. These are presumed to be immutable properties of the universe. (We're not so sure anymore.)

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<img src="https://tex.z-dn.net/?f=%28%20%5Cfrac%7B3%7D%7B4%7D%20%20-%20%20%5Cfrac%7B2%7D%7B3%7D%20%29%20%5Ctimes%201%20%5Cfrac%7
fomenos

Answer: 0.1 or 1/10

Step-by-step explanation:

\left(\frac{3}{4}-\frac{2}{3}\right)\cdot \:1\frac{1}{5}

1\frac{1}{5}=\frac{6}{5}

\left(\frac{3}{4}-\frac{2}{3}\right)\cdot \frac{6}{5}

  \frac{3}{4}-\frac{2}{3}    =\frac{9}{12}-\frac{8}{12}

=\frac{1}{12}

\frac{6}{5}\cdot \frac{1}{12}

Cross, cancel common factor

\frac{1}{2}\cdot \frac{1}{5}

=\frac{1}{10}

6 0
3 years ago
One factor in flood safety along a levee is the area that will absorb water should the levee break. The coordinates that make up
Anit [1.1K]

Let

A(0,0)\\ B (2.8, 2.1)\\C(4.3, 4.4)

using a graph tool

see the attached figure

The figure is a triangle

we know that

<u>The Heron's Formula</u> is a method for calculating the area of a triangle when you know the lengths of all three sides.

Hero's Formula is equal to

Area=\sqrt{p*(p-a)*(p-b)*(p-c)}

where

p is  is half the perimeter of the triangle

 a,b,c are the lengths of the sides of a triangle

so

Step 1

<u>Find the length sides of the triangle</u>

a) <u>Find the distance AB</u>

d =\sqrt{(y2-y1)^{2} +(x2-x1)^{2}}

Substitute

d =\sqrt{(2.1-0)^{2} +(2.8-0)^{2}}

d =3.5\ mi}

b) <u>Find the distance AC</u>

d =\sqrt{(y2-y1)^{2} +(x2-x1)^{2}}

Substitute

d =\sqrt{(4.4-0)^{2} +(4.3-0)^{2}}

d =6.15\ mi}

c) <u>Find the distance BC</u>

d =\sqrt{(y2-y1)^{2} +(x2-x1)^{2}}

Substitute

d =\sqrt{(4.4-2.1)^{2} +(4.3-2.8)^{2}}

d =2.75\ mi}

Step 2

<u>Find the perimeter of the triangle</u>

Perimeter= 3.5+6.15+2.75 =12.4\ mi

<u>Find the half of the perimeter </u>

p=\frac{12.4}{2} = 6.2\ mi

Step 3

<u>Find the area of the triangle</u>

Area=\sqrt{6.2*(6.2-3.5)*(6.2-6.15)*(6.2-2.75)}

Area=\sqrt{6.2*(2.7)*(0.05)*(3.45)}

Area= 1.69\ mi^{2}

therefore

<u>the answer is the option </u>

a) 1.65 mi^2.

4 0
3 years ago
Read 2 more answers
Give an example of a quadratic equation with 2 + 3i as one of its solutions
Anastasy [175]

Answer:

Step-by-step explanation:

roots are (2+3i) and (2-3i)

reqd. eq. is (x-2-3i)(x-2+3i)=0

or (x-2)²-(3i)²=0

or x²-4x+9-9i²=0

or x²-4x+9+9=0

or x²-4x+18=0

5 0
3 years ago
Which ratio does not belong with the other three? Explain your reasoning. 4/10 2/5 3/5 6/15
JulsSmile [24]

Answer:

3/5

Step-by-step explanation:

7 0
3 years ago
Graph f(x) = 2x^4+3 <br> let x = 0, 1, and 2.<br> please show your work
mestny [16]
Sub those points for x
f(x) is the y

(x,y)

so for x=0
f(0)=2(0)^4+3
f(0)=0+3
f(0)=3
(0,3) is a opint

for x=1
f(1)=2(1)^4+3
f(1)=2(1)+3
f(1)=2+3
f(1)=5
(1,5) is another point

for x=2
f(2)=2(2^4)+3
f(2)=2(16)+3
f(2)=32+3
f(2)=35
(2,35) is another point


points are
(0,3)
(1,5)
(2,35)
3 0
3 years ago
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