Assuming that there are N lanes and runners are running in the middle of each lane,
width of each lane = (1/N) [m]turning of first lane = π×(R+(1/N)×(1/2))
turning of second lane = π×(R+((1/N)×(1/2))+(1/N))
you can get the difference in turning lane simply by subtracting turning of first lane from turning of second lane.
If i worked the problem correctly, it should be π×(1/N) meter difference between each lane
Points on BC:
(-5, 5) and (0,1)
Slope = (5-1)/(-5-0)
Slope = -4/5
y = mx + c
y = -4/5x + c
at point (0,1)
1 = -4/5(0) + c
c = 1
y = -4/5x + 1
5y = -4x + 5
4x + 5y = 5 (Answer D)
(9,-36)
X=9 Y= -36
-3x-9=1/3x-39
Solve it
The answer is x=9
Y=-3x-9
Y= -3(add the 9 because 9 is equal x) -9
Y=-3(9)-9
Solve it
The answer is y=-36
Given:
f(x) = 4x² + 1
g(x) = x² - 5
Then
(f + g)(x) = 4x² + 1 + x² - 5
= 5x² - 4
Answer: 5x² - 4
Answer:
X = 10.7
Step-by-step explanation:
25^2 - 16^2 = 369 which squared is approximately 19.2. We need X which is the smaller side so we minus 22^2 from 19.2^2 which is 115.36 which is squared to 10.7
