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Nastasia [14]
3 years ago
14

What is the domain and the range for the (2,3),(4,1),(5,-3),(-9,9)

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
8 0

Answer:

Domain : {-9, 2,4,5}

Range:  { -3,1,3,9}

Step-by-step explanation:

The domain is the input values

The domain is the x values in the pairs

Domain : {2,4,5,-9}

We usually put them in numerical order

Domain : {-9, 2,4,5}

The range is the output values

The  range is the y values in the pairs

Range : { 3,1,-3,9}

We usually put them in numerical order

Range:  { -3,1,3,9}

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(If there's a plus sign before the whole parentheses, then just erase the parentheses.  If there's a minus sign before the whole thing, then change the sign of each term inside, and erase the parentheses.)

-- Add up all the  x² terms.
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             x² + x² = 2x²
or
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4 0
3 years ago
A baseball player throws a 95mph fastball straight up into the air. The position equation, which gives the height of the ball at
Lana71 [14]
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3 0
3 years ago
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It’s the one you are on
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3 years ago
The sample space of a random experiment is {a, b, c, d, e} with probabilities 0.1, 0.1, 0.2, 0.4, and 0.2 respectively. Let A de
antoniya [11.8K]

Answer:

a) P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4

b) P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8

c) P(A') = 1-P(A) =1-0.4=0.6

d) P(A \cup B) =0.4 +0.8-0.2 =1.0

e)  The intersection between the set A and B is the element c so then we have this:

P(A \cap B) = P(c) =0.2

Step-by-step explanation:

We have the following space provided:

S= [a,b,c,d,e]

With the following probabilities:

P(a) =0.1, P(b)=0.1, P(c) =0.2, P(d)=0.4, P(e)=0.2

And we define the following events:

A= [a,b,c], B=[c,d,e]

For this case we can find the individual probabilities for A and B like this:

P(A) = 0.1+0.1+0.2 = 0.4

P(B) =0.2+0.4+0.2=0.8

Determine:

a. P(A)

P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4

b. P(B)

P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8

c. P(A’)

From definition of complement we have this:

P(A') = 1-P(A) =1-0.4=0.6

d. P(AUB)

Using the total law of probability we got:

P(A \cup B) =P(A) +P(B)-P(A \cap B)

For this case P(A \cap B) = P(c) =0.2, so if we replace we got:

P(A \cup B) =0.4 +0.8-0.2 =1.0

e. P(AnB)

The intersection between the set A and B is the element c so then we have this:

P(A \cap B) = P(c) =0.2

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Well the first problem that i solve is you have to move 12 it will give you 
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