Answer:
(4x^2 +9)(4x^2-9) =0
Step-by-step explanation:
16x^4 - 18 = 0
Rewriting
(4x^2)^2 - 9^2 =0
We notice that this is the difference of squares
a^2 - b^2 = (a-b)(a+b)
(4x^2 -9)(4x^2+9) =0
Circumference of a circle =2πr
6.28=2πr
3.14=πr
3.14/π=r
3.14/3.14=r
<h2>therefore,r=1</h2>
I don't understand sorry but I speak another language English
Sin(A) = opposite/hypotenuse = 12/13
Cos(A) = adjacent/hypotenuse = 5/13
Tan(A) = opposite/adjacent = 12/5