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ycow [4]
3 years ago
10

Each person in a large square occupies, on average, 2.5 sq. feet of space. Estimate the number of people that can comfortably st

and on the gym floor if the gym is 50 feet wide and 100 feet long.
A. 2000 people

B. 5000 people

C. 10,000 people

D. 12,500 people

Mathematics
2 answers:
Dima020 [189]3 years ago
4 0
Your answer should be C , hope this helps !!
Aleksandr [31]3 years ago
3 0

Answer:

2000 people

Step-by-step explanation:

The area of the gym is the width times length:

A = wl

A = (50 ft) (100 ft)

A = 5000 ft²

Write a proportion:

1 person / 2.5 ft² = x / 5000 ft²

x = 2000 people

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Help please i’m not really sure what the answer is
Maslowich

Answer:

The area is 48

The perimeter is 32

4 0
3 years ago
In (r,theta), the value of theta can be negative.<br>True or False
Marizza181 [45]

(r,theta) represents polar coordinate .

And in (r,theta), there is neither any restriction on r nor on theta. It means both r and theta can either be positive or negative .

For e.g. (2,30 degree), (2,-30 degree) both are correct .

So the given statement is true .

5 0
2 years ago
What is 13 hours after 4:00 am.
kupik [55]
I believe it would be 5:00 pm, because 12 hours after 4:00 am is 4:00 pm, plus one hour is 5:00pm.
8 0
3 years ago
Read 2 more answers
(HELP MEH) Why is √​5​​ irrational?
xxTIMURxx [149]

Answer:

  D.)  because it cannot be expressed as a ratio of integers

Step-by-step explanation:

The root of any integer that is not a perfect square is irrational. 5 is not a perfect square, so is irrational—it cannot be expressed as the ratio of integers.

__

<em>Proof</em>

Suppose √5 = p/q, where p and q are mutually prime. Then p² = 5q².

If p is even, then q² must be even. We know that √2 is irrational, so the only way for q² to be even is for q to be even—contradicting our requirement on p and q.

If p is odd, then both p² and q² will be odd. We can say p = 2n+1, and q = 2m+1, so we have ...

  p² = 5q²

  (2n+1)² = 5(2m+1)²

  4n² +4n +1 = 20m² +20m +5

  4n² +4n = 4(4m² +4m +1)

  n(n+1) = (2m+1)²

The expression on the left will be even for any integer n; the expression on the right will be odd for any integer m. This equation cannot be satisfied for any integers m and n, so contradicting our assumption √5 = p/q.

We have shown using "proof by contradiction" that √5 cannot be the ratio of integers.

4 0
3 years ago
How do i solve 6m_2=m+13
I am Lyosha [343]
If it's addition you do the opposite which is subtraction and that's the answer that you get so 6m_2=m+13 so add 6-2=4 and then 13-4=9
7 0
2 years ago
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