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3 years ago

How many solutions does the following equation have: 16y + 7 = -3y + 10 + 8y

Mathematics

2 answers:

joja [24]3 years ago

7 0

Answer:

one solution only

Step-by-step explanation:

16y + 7 = -3y + 10 + 8y

16y + 3y - 8y = 10 - 7

11y = 3

y = 3/11

irakobra [83]3 years ago

4 0

One solution because you get an answer in the end

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Read 2 more answers

A/ab-bsquare + b/ab-asquare?

lord [1]

Answer:

$\dfrac{(a+b)}{ab}$

Step-by-step explanation:

The given expression is :

$\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}$

It can be solved as follows :

$\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}=\dfrac{a}{b(a-b)}+\dfrac{b}{a(b-a)}\\\\=\dfrac{a}{b(a-b)}+\dfrac{b}{-a(-b+a)}\\\\=\dfrac{1}{a-b}(\dfrac{a}{b}-\dfrac{b}{a})\\\\=\dfrac{a^2-b^2}{ab(a-b)}\\\\=\dfrac{(a-b)(a+b)}{ab(a-b)}\\\\=\dfrac{(a+b)}{ab}$

So, the solution of the given expression is equal to $\dfrac{(a+b)}{ab}$ .

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3 years ago