To solve for proportion we make use of the z statistic.
The procedure is to solve for the value of the z score and then locate for the
proportion using the standard distribution tables. The formula for z score is:
z = (X – μ) / σ
where X is the sample value, μ is the mean value and σ is
the standard deviation
when X = 70
z1 = (70 – 100) / 15 = -2
Using the standard distribution tables, proportion is P1
= 0.0228
when X = 130
z2 = (130 – 100) /15 = 2
Using the standard distribution tables, proportion is P2
= 0.9772
Therefore the proportion between X of 70 and 130 is:
P (70<X<130) = P2 – P1
P (70<X<130) = 0.9772 - 0.0228
P (70<X<130) = 0.9544
Therefore 0.9544 or 95.44% of the test takers scored
between 70 and 130.
To solve this problem, we first have to convert 5 1/2 into an improper fraction. To do this, we multiply the unit (5) times the denominator (2) and then add the numerator (1) to the product, while still keeping the same denominator.
(5 * 2) + 1 = 10 + 1 = 11/2
Now, this makes our expression: 11/2 - 2/3
Next, we have to find a common denominator for 2 and 3 by finding their shared LCM, or least common multiple. In this case, the LCM is 6. This means that we are going to convert both of the fractions in the expression into fractions with the denominator 6, so that we can easily compute the subtraction.
11 * 3 / 2 * 3 - 2 * 2 / 3 * 2
33/6 - 4/6
Now, we can simply subtract the numerators to find our final answer.
29/6
Your final answer is 29/6.
Hope this helps!
To find the answer, you will just subtract 4.56 from 10.
The answer is no y varies 8 x varies 2
4:44 pm but I might be wrong.