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Doss [256]
3 years ago
12

An outdoor Wi-Fi unit for a picnic area has a 110 mW output and a range of about 38 m. What output power (in mW) would reduce it

s range to 18 m for use with the same devices as before? Assume there are no obstacles in the way and that microwaves into the ground are simply absorbed.
Physics
1 answer:
valkas [14]3 years ago
8 0

Answer:

The output power is 24.68 mW.

Explanation:

Given that,

Power = 110 mW

Range = 38 m

Reduced range = 18 m

We need to calculate the power

Using formula of intensity

I=\dfrac{P}{A}

I=\dfrac{P}{\pi r^2}

As intensity is constant

P\propto r^2

So, \dfrac{P_{1}}{P_{2}}=\dfrac{r_{1}^2}{r_{2}^{2}}

P_{2}=\dfrac{r_{2}^2}{r_{1}^{2}}\timesP_{1}

Put the value into the formula

P_{2}=\dfrac{18^2}{38^2}\times110\times10^{-3}

P_{2}=24.68\times10^{-3}\ W

P_{2}=24.68\ mW

Hence, The output power is 24.68 mW.

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A 15.0 Ohms resistor is connected in series to a 120V generator and two 10.0 Ohms resistors that are connected in parallel to ea
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Hi there! :)

Reference the diagram below for clarification.

1.

We must begin by knowing the following rules for resistors in series and parallel.

In series:
R_T = R_1 + R_2 + ... + R_n

In parallel:
\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}

We can begin solving for the equivalent resistance of the two resistors in parallel using the parallel rules.

\frac{1}{R_{T, parallel}} = \frac{1}{10} + \frac{1}{10}\\\\\frac{1}{R_{T, parallel}} = \frac{2}{10} = \frac{1}{5}\\\\R_{T, parallel} = 5\Omega

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R_T = 15 + 5\\\\\boxed{R_T = 20 \Omega}

2.

We can use Ohm's law to solve for the current in the circuit.

i = \frac{V}{R_T}\\\\i = \frac{120}{20} = \boxed{6 A}

3.

For resistors in series, both resistors receive the SAME current.

Therefore, the 15Ω resistor receives 6A, and the parallel COMBO (not each individual resistor, but the 5Ω equivalent when combined) receives 6A.

In this instance, since both of the resistors in parallel are equal, the current is SPLIT EQUALLY between the two. (Current in parallel ADDS UP). Therefore, an even split between 2 resistors of 6 A is <u>3A for each 10Ω resistor</u>.

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Since the 15.0 Ω resistor receives 6A, we can use Ohm's Law to solve for voltage.

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4 0
1 year ago
The bending of light as it passes into a transparent material of different optical intensity is known as A. conversion. B. aberr
stiks02 [169]

Answer:

<em>D. refraction</em>

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<em>Refraction occurs when light travels from air to glass or from air to liquid.</em>

<em>Laws Of Refraction:</em>

(i) The incident ray, the refracted ray and the normal, all at the point of incident lies in the same plane.

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6 0
3 years ago
A small block with mass 0.0400 kg is moving in the xy-plane. The net force on the block is described by the potentialenergy func
OlgaM077 [116]

Answer:

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Explanation:

Given that

U(x,y) = (6.00  )x²  - (3.75  )y ³

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Now force in the x-direction

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Mrrafil [7]

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Explanation:

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4 0
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