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Doss [256]
3 years ago
12

An outdoor Wi-Fi unit for a picnic area has a 110 mW output and a range of about 38 m. What output power (in mW) would reduce it

s range to 18 m for use with the same devices as before? Assume there are no obstacles in the way and that microwaves into the ground are simply absorbed.
Physics
1 answer:
valkas [14]3 years ago
8 0

Answer:

The output power is 24.68 mW.

Explanation:

Given that,

Power = 110 mW

Range = 38 m

Reduced range = 18 m

We need to calculate the power

Using formula of intensity

I=\dfrac{P}{A}

I=\dfrac{P}{\pi r^2}

As intensity is constant

P\propto r^2

So, \dfrac{P_{1}}{P_{2}}=\dfrac{r_{1}^2}{r_{2}^{2}}

P_{2}=\dfrac{r_{2}^2}{r_{1}^{2}}\timesP_{1}

Put the value into the formula

P_{2}=\dfrac{18^2}{38^2}\times110\times10^{-3}

P_{2}=24.68\times10^{-3}\ W

P_{2}=24.68\ mW

Hence, The output power is 24.68 mW.

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Are the two expressions equvalent 7(8x+5) and 48x + 35
Evgesh-ka [11]
Yes they are equivalent because 7x5=35 and 8x x 5=48x
4 0
3 years ago
Observe the given figure and find the the gravitational force between m1 and m2.​
Leno4ka [110]

Answer:

The gravitational force between m₁ and m₂, is approximately 1.06789 × 10⁻⁶ N

Explanation:

The details of the given masses having gravitational attractive force between them are;

m₁ = 20 kg, r₁ = 10 cm = 0.1 m, m₂ = 50 kg, and r₂ = 15 cm = 0.15 m

The gravitational force between m₁ and m₂ is given by Newton's Law of gravitation as follows;

F =G \cdot \dfrac{m_{1} \cdot m_{2}}{r^{2}}

Where;

F = The gravitational force between m₁ and m₂

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

r₂ = 0.1 m + 0.15 m = 0.25 m

Therefore, we have;

F = 6.67430 \times 10^{-11} \ N \cdot m^2/kg \times \dfrac{20 \ kg\times 50 \ kg}{(0.1 \ m+ 0.15 \ m)^{2}} \approx 1.06789 \times 10^{-6} \ N

The gravitational force between m₁ and m₂, F ≈ 1.06789 × 10⁻⁶ N

8 0
2 years ago
The magnitude of electrical force between a pair of charged particles is ____ as much when the particles are moved half as far a
Gnesinka [82]

The magnitude of the electrical force between a pair of charged particles is 4 Times as much when the particles are moved half as far apart.

This can be easily understood by Columb's law,

F_{new} = \frac{kQ_{1}Q_{2}}{r^{2}}

which state's that the amount of electrical force experienced by two charged particles is inversely proportional to the square of the distance between them.

∴ \frac{F_{new} }{F_{old} } = \frac{Distance_{new}^{2}  }{Distance_{old}^{2}  }

Now, we know the new distance is half the original distance,

F_{new} = \frac{kQ_{1}Q_{2}}{\frac{r}{2}^{2} } \\F_{new} = 4\frac{kQ_{1}Q_{2}}{r^{2}}

F_{new} = 4F_{old}

The electrical force of attraction or electrostatic force of attraction between two charged particles refers to the amount of attractive or repulsive force that exists between the two charges. This can be calculated by Columb's Law.

A charged particle in physics is a particle that has an electric charge. It might be an ion, such as a molecule or atom having an excess or shortage of electrons in comparison to protons. The same charge is thought to be shared by an electron, a proton, or another primary particle.

Learn more about electrical force here

brainly.com/question/2526815

#SPJ4

8 0
1 year ago
2. What is the power rating of an engine capable of lifting a 100 kg object 5 m vertically
Leya [2.2K]
Work=f.d
Work=100*50 = 500
Power = work/time = 500/4
=125 watt
7 0
3 years ago
Which model best represents a pattern?
balandron [24]
The water cycle because <span>the cycle of processes by which water circulates between the earth's oceans, atmosphere, and land, involving precipitation as rain.

it is like a pattern

hope that was helpful.</span>
3 0
3 years ago
Read 2 more answers
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