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Travka [436]
3 years ago
11

The atmospheric pressure on the top of the Engineering Sciences Building (ESB) is 97.6 kPa, while that in Room G39-ESB (ground f

loor) is 98.2 kPa.
Determine the height of the building if the air density is assumed to be independent of the height, being 1.16 kg/m³, while the acceleration of gravity is 9.81 N/kg.
Physics
1 answer:
Stells [14]3 years ago
6 0

Answer:

Δ h = 52.78 m

Explanation:

given,

Atmospheric pressure at the top of building = 97.6 kPa

Atmospheric pressure at the bottom of building = 98.2 kPa

Density of air = 1.16 kg/m³

acceleration due to gravity, g = 9.8 m/s²

height of the building = ?

We know,

Δ P = ρ g Δ h

(98.2-97.6) x 10³ = 1.16 x 9.8 x Δ h

11.368 Δ h = 600

Δ h = 52.78 m

Hence, the height of the building is equal to 52.78 m.

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and subtract the inside volume from the outside volume.  That's
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But look.  This 'shell' (the 0.95 mile of water) is only about  1530 meters thick,
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So I want to do this problem the easier way ... Let's say that the volume
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The area of a sphere is  4 pi Radius² .
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We're only interested in 70% of the total surface area.

                   =   (0.7) x (4 pi) x (40.58 x 10¹²) m²

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We have to change that 0.95 mile to meters.
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Now we're ready to dump all the numbers into the machine and
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This is my answer, and I'm stickin to it.

But ... just like all the other problems you get in high school, the
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I don't know how much effort you put into this problem, but somewhere
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