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4 years ago

If we increase the amount of work being done, and all other factors remain the same, the amount of power would

Physics

1 answer:

BlackZzzverrR [31]4 years ago

4 0

The amount of power would increase
P=W/t
P is directly proportional to W

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Calculate the speed of a person who walked 100 m in 25 seconds. Show all of your work. Step 1: Using a light color, highlight th

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Answer:

4 m/s

Explanation:

to find m/s, divide the meters term by the seconds term. 100m/25s = 4m/s

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3 years ago

What’s the most distant object in the solar system

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Answer:

pluto

Explanation:

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3 years ago

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If a biker starts at rest and accelerates to 15 m/s in 7.5 seconds, what is his<br> acceleration? *

sergeinik [125]

Answer:

2 m/s^2

Explanation:

from the question

v=15 m/s

t=7.5

a=?

from the first equation of motion

v=u+at

where,

v=final velocity

u=initial velocity

a=acceleration

t=time

from the question (u) will be zero because the body started at rest

v=u+at

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3 years ago

2. Another car weighs 2000kg, you can push it .05 m/s?, how much force are you

Vesna [10]

Answer:

$\boxed {\boxed {\sf 100 \ Newtons}}$

Explanation:

We are asked to calculate the force you are applying to a car. According to Newton's Second Law of Motion, force is the product of mass and acceleration. Therefore, we can use the following formula to calculate force.

$F= m \times a$

The mass of the car is 2000 kilograms and the acceleration is 0.5 meters per second squared.

m= 2000 kg
a= 0.05 m/s²

Substitute the values into the formula.

$F= 2000 \ kg \times 0.05 \ m/s^2$

Multiply.

$F= 100 \ kg *m/s^2$

Convert the units. 1 kilogram meter per second squared is equal to 1 Newton. Our answer of 100 kilogram meters per second square is equal to 100 Newtons.

$F= 100 \ N$

You apply <u>100 Newtons</u> of force to the car.

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3 years ago

As a person squeezes and applies pressure to the outside of a balloon, air particles inside

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As a person squeezed and applies the pressure to the outside of a balloon, the air particle inside the balloon gains energy and collide with each other, the particle of the air also try leave the balloon surface will implies equal pressure on the wall of the balloon, as the pressure outside the balloon increase, the inside pressure will also increase.

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3 years ago