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allochka39001 [22]

3 years ago

10

The slope, m, of a linear equation can be found using the formula m = , where the x- and y-values come from two ordered pairs, a

nd (x1, y1) and (x2, y2).

2 answers:

tino4ka555 [31]3 years ago

5 0

The answer is y2 = m(x2 – x1) + y1 i believe.

Nikitich [7]3 years ago

3 0

Answer with explanation:

→Suppose ,y= mx +c, is a linear equation and the line passes through two points , $(x_{1},y_{1}),(x_{2},y_{2})$ .

→Slope of line joining two points having coordinates , $(x_{1},y_{1}),(x_{2},y_{2})$ can be obtained by the formula

$m=\frac{\text{Difference of y coordinates}}{\text{Difference of x coordinates}}\\\\m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

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Serggg [28]

Maaaaane I’m sorry I can’t help

4 0

3 years ago

A Ferris wheel can accommodate 65 people in 30 minutes how many people could ride the Ferris wheel in 2 hours what was the rate

erik [133]

$65 \times 4 = 260$
260 can ride the ferris wheel in 2 hours.
$65 \times 2 = 130$
130 people is the rate per hour.

5 0

3 years ago

A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of

Ivenika [448]

The equation for the height of the rocket at time t given

$h= -16t^2+192t$

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

$h= -16t^2+192t$

$560 = -16t^2+192t$

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

$560 = -16(t^2 - 12t)$

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

$560/-16 = -16(t^2-12t)/-16$

$-35 = t^2 -12t$

Now we will move -35 to the righ side by adding 35 to both sides.

$-35+35 = t^2-12t+35$

$0 = t^2 -12t+35$

$t^2-12t+35 = 0$

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

$t^2-12t+35 =0$

$(t-5)(t-7) =0$

So by using zero product property we will get

$t-5 =0$

$t-5+5 = 0+5$

$t=5$

Also $t-7 =0$

$t-7+7 = 0+7$

$t=7$

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

$h= -16t^2+192t$

$0= -16t^2 + 192 t$

$0 = -16(t^2-12t)$

$-16(t^2-12t) = 0$

We will move -16 to the other side by dividing it to both sides.

$-16(t^2-12t)/-16 = 0/-16$

$t^2-12t = 0$

We will take out the common factor t from the left side. By taking out t we will get,

$t(t-12) = 0$

We will use zero product property now. By using that we will get,

$t = 0$

ans also $t-12 = 0$

$t-12+12 = 0+12$

$t = 12$

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0

3 years ago

I need help please help

Vedmedyk [2.9K]

Answer:

$m(x)=x^4-x^3+8x-1\\\\n(x)=|x+6|$

Are not one-to-one functions

Step-by-step explanation:

As m(x) has symmetry at the line x=0, it is not one-to-one

As n(x) has symmetry at the line x=-6, it is not one-to-one

8 0

3 years ago

Is there a relationship between the area and the perimete of a rectangle. Explain

Nady [450]

The area is another way of say perimeter. it's the inside area of the rectangle

5 0

3 years ago