Answer:
If i have three moles of a gas at a pressure of 5.6 atm and a volume of 3 liters, what is the temperature ?
We have the following data:
n (number of moles) = 3 moles
P (pressure) = 5.6 atm
V (volume) = 12 L
T (temperature) = ? (in Kelvin)
R (gas constant) = 0.082 atm.L / mol.K
We apply the data above to the Clapeyron equation (gas equation), let's see:
Answer:
The temperature is approximately 205 Kelvin
1. Regroup terms
x(x+5)=104
2. Expand
x^2+5x=104
3. Move all terms to one side
x^2+5x-104=0
4. Factor x^2+5x-104
(x-8)(x+13)=0
5. Solve for x
x=8 or x=-13
Since x<0 is not possible in this case, x=8
6. Finding the dimensions
We know that one side has to be x+5, and now that we know x:
8+5=13
13*8=104
The dimensions are 13 and 8, have a nice day :D
Reciprocal is another word for flip...... So like, 3/4, when you recriprocal it, it would be 4/3! Hope this helps!
U first find the common denominator which is 8
Then subtract to get 7/8
I am to believe that his score was 70.
since mike scored 15 less than 85 i had suspected it was 70
