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umka21 [38]
3 years ago
15

I need to find the volume as a function of the diameter! Pls help!! :’D

Mathematics
1 answer:
Lelechka [254]3 years ago
8 0

Answer:

V=( 1/6 )* π * d³

Step-by-step explanation:

We khow that d= 2r⇒ r=d/2

  • so r³= d³/8
  • substitute r with d³/8
  • V= (4/3)*π*(d³/8) = (4/3*8)*d³*π = (1/6 )* d³ *π

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6. The vertices of ALMN are L(7,4), M(7,16), and
max2010maxim [7]

Answer:

(a) LM=12 units, LN=35 units, MN=37 units

(b)8 84 units

(c) 210 square units

Step-by-step explanation:

(a)

Since points L and M have same x coordinates, it means they are in the same plane. Also, since the Y coordinates of L and N are same, they also lie in the same plane

Length LM=\sqrt {(7-7)^{2}+(16-4)^{2}}=12 units

Length LN=\sqrt {(42-7)^{2}+(4-4)^{2}}=35 units

LengthMN=\sqrt {(42-7)^{2}+(4-16)^{2}}=37 units

Alternatively, since this is a right angle triangle, length MN is found using Pythagoras theorem where

MN=\sqrt {(LN)^{2}+(LM)^{2}}=\sqrt {(12)^{2}+(35)^{2}}=37 units

Therefore, the lengths LM=12 units, LN=35 units and MN=37 units

(b)

Perimeter is the distance all round the figure

P=LM+LN+MN=12 units+35 units+37 units=84 units

(c)

Area of a triangle is given by 0.5bh where b is base and h is height, in this case, b is LN=35 units and h=LM which is 12 units

Therefore, A=0.5*12*35= 210 square units

4 0
3 years ago
A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y
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Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32


Given that 100 beetles are released into a field.

So that means initial number of beetles P=100


Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

A=P(1+r)^n where A is number of beetles at any year n.

Plug the given values into above formula we get:

A=100(1+0.32)^n

A=100(1.32)^n


now plug n=10 years

A=100(1.32)^{10}=100(16.0597696605)=1605.97696605

Hence answer is approx 1606 beetles will be there after 20 years.


Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

A=100(1.32)^{20}=100(257.916201549)=25791.6201549

Hence answer is approx 25791 beetles will be there after 20 years.



Now we have to find time for 100000 beetles so plug A=100000

A=100(1.32)^n

100000=100(1.32)^n

1000=(1.32)^n

log(1000)=n*log(1.32)

\frac{\log\left(10000\right)}{\log\left(1.32\right)}=n

33.174666862=n

Hence answer is approx 33 years.

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