Answer: - 0.027
Step-by-step explanation:
Win = any even number between (0 - 36)
Therefore,
Lose = any odd number between 0 —36 including 0
Assume Bet amount = $1
Expected value is calculate by summing all possible outcomes by their respective probabilities.
Expected value = [(p(winning) × net win value) + (p(losing +net loss value]
P(winning) = p(even) = 18/37
P(losing) = p(odd) +p(0) = 19/37
Net win value = $2
Net loss value = $-1
Expected value = [(18/37) × ($1) + (19/37) × (-$1)]
Expected value = 0.48648648 - 0.51351351
Expected value = - 0.027
Answer:
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Answer:
no I do not agree, Because it doesn't make since
Answer:
Shown
Step-by-step explanation:
Given that twelve basketball players, whose uniforms are numbered 1 through 12, stand around the center ring on the court in an arbitrary arrangement.
Let us consider consecutive numbers in this set.

After this we find the totals are more than 20.
When 1 to 12 are arbitrarily arranged, there are chances that numbers from 6 and above are having consecutive numbers.
These totals are greater than 20
Hence shown that some three consecutive players have the sum of their numbers at least 20.
(i.e. starting from if we take)