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Mrrafil [7]
3 years ago
7

Steps to solve 3 (x -5) + 7 x = 65

Mathematics
2 answers:
Novay_Z [31]3 years ago
8 0

Answer:

x = 8

Step-by-step explanation:

3(x-5)+6x = 3x-15+7x

3x-15+7x = 65

10x = 80

x = 8

yanalaym [24]3 years ago
3 0

To solve this, you need to isolate/get the variable "x" by itself in the equation:

3(x - 5) + 7x = 65      Distribute 3 into (x - 5)

(3)x + (3)(-5) + 7x = 65

3x - 15 + 7x = 65     Combine like terms(terms that have the same variable and power/exponent), or combine 3x and 7x

10x - 15 = 65    Add 15 on both sides

10x - 15 + 15 = 65 + 15

10x = 80    Divide 10 on both sides to get "x" by itself

\frac{10x}{10} =\frac{80}{10}

x = 8

PROOF

3(x - 5) + 7x = 65     Substitute/plug in 8 into "x" since x = 8

3(8 - 5) + 7(8) = 65

3(3) + 56 = 65

9 + 56 = 65

65 = 65

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2. Solve the system of equations. Write your answer in parametric vector notation. X, +5x2 + 4x3 + 3x4 +9xs = 18 2x, +6x2 + 4x3
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The system is inconsistent.

Step-by-step explanation:

The system is

x_1+5x_2+4x_3+3x_4+9x_5=18\\2x_1+6x_2+4x_3+6x_4+6x_5=28\\3x_1+7x_2+4x_3+10x_4+x_5=41\\4x_1+6x_2+2x_3+7x_4+4x_5=29

The associated matrix to the system is

\left[\begin{array}{cccccc}1&5&4&3&9&18\\2&6&4&6&6&28\\3&7&4&10&1&41\\4&6&2&7&4&29\end{array}\right]

Now we use row operations to find the echelon form of the matrix:

1. We substract to row 2, two times the row 1.

We substract to row 3, three times the row 1.

We substract to row 4, four times the row 1 and obtain the matrix

\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&-4&-4&0&-12&-8\\0&-8&-8&1&-26&-13\\0&-14&-14&-5&-32&-43\end{array}\right]

2. We multiply the second row of the preview step by -1/4. We obtain the matrix

\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&-8&-8&1&-26&-13\\0&-14&-14&-5&-32&-43\end{array}\right]

3.

We add to row 3, eight times the row 2.

We add to row 4, fourtheen times the row 2 and obtain the matrix

\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&0&0&1&-2&3\\0&0&0&-5&10&-155\end{array}\right]

4. We add to row 4 of the preview step, five times the row 3 and obtain the matrix

\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&0&0&1&-2&3\\0&0&0&0&0&-140\end{array}\right]

Using backward substitution we have that

0x_5=-140, then 0=-140 and this is absurd. Then The system is inconsistent.

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