Robby had 4 4/9 bags of pet food.All of the bags held the same amount of food when they were full.Of Robby's 4 4/9 bags of pet f
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Answer:
1. The value of the variable, y is 11
2. (B) QRS is congruent to segment (E) ΔWXY by the hypotenuse leg congruency criteria
Step-by-step explanation:
1. The lengths of the sides of the given triangles ABC are AB = 14, BC = 27, AC = 19, and ∡A = 32°
The lengths of the sides of the given triangle FGH, FG = 14, GH = 19, FH = 2y + 5, ∡G = 32°
From the given parameters, we have;
Segment AB (AB = 14) is congruent to segment FG (FG = 14)
Segment AC (AC = 19) is congruent to segment GH (GH = 19)
Angle ∡A (∡A = 32°) is congruent to angle ∡G (∡G = 32°)
∴ ΔBAC is congruent to ΔFGH by the Side-Angle-Side rule of congruency
Therefore, segment BC is congruent to segment FH by Congruent Parts of Congruent Triangle are Congruent, CPCTC
Segment BC = Segment FH by definition of congruency
∴ 27 = 2·y + 5
2·y + 5 = 27
2·y = 27 - 5 = 22
y = 22/2 = 11
y = 11
The value of the variable, y = 11
2. For option A. the vertices of triangle ABC are A(-7, 4), B(-4, 1), C(-2, 5)
The length of the sides are;
The length of side AB = √((-4 - (-7))² + (1 - 4)²) = 3·√2
The length of side BC = √((-4 - (-2))² + (1 - 5)²) = √20
The length of side AC = √((-2 - (-7))² + (5 - 4)²) = √26
For option B. the vertices of triangle QRS are Q(3, -4), R(3, -1), S(7, -1)
The length of the sides are;
The length of side QR = √((3 - 3)² + ((-4) - (-1))²) = 3
The length of side RS = √((7 - 3)² + (-1 - (-1))²) = 4
The length of side QS = √((3 - 7)² + ((-4) - (-1))²) = 5
For option C. the vertices of triangle DEF are D(-2, 6), E(1, 3), F(3, 7)
The length of the sides are;
The length of side DE = √(((-2) - 1)² + (6 - 3)²) = 3·√2
The length of side EF = √((3 - 1)² + (7 - 3)²) = √20
The length of side DF = √((3 - (-2))² + (7 - 6)²) = √26
For option D. the vertices of triangle TUV are T(-6, -5), U(-6, 1), V(4, 1)
The length of the sides are;
The length of side TU = √(((-6) - (-6))² + ((-5) - 1)²) = 6
The length of side UV = √(((-6) - 4)² + (1 - 1)²) = 10
The length of side TV = √(((-6) - 4)² + ((-5) - 1)²) = 2·√34
For option E. the vertices of triangle WXY are W(-6, 4), X(-6, 1), Y(-2, 1)
The length of the sides are;
The length of side WX = √(((-6) - (-6))² + (4 - 1)²) = 3
The length of side XY = √(((-6) - (-2))² + (1 - 1)²) = 4
The length of side WY = √(((-6) - (-2))² + (4 - 1)²) = 5
Therefore;
Segment QR of ΔQRS is congruent to segment WX of ΔWXY
Segment RS of ΔQRS is congruent to segment XY of ΔWXY
Segment QS of ΔQRS is congruent to segment WY of ΔWXY
Whereby QS and WY are the hypotenuse side of ΔQRS and ΔWXY respectively, because QS = WY = 5 = √( +
) = (√(3² + 4²)
and also RS = XY, by the definition of congruency, we have;
QRS is congruent to segment ΔWXY by the hypotenuse leg congruency criteria
Answer:
2 seconds
Step-by-step explanation:
Given that:
h = -16t² + 28t + 8
Using quadratic formula:
where;
a = -16
b = +28
c = +8
Since we are considering the positive value; Then it will take the snowboarder 2 seconds before it hits the ground.
Answer:
see below
Step-by-step explanation:
A graphing calculator makes this a lot easier. You can also do it with a spreadsheet program. The default for most tools is for the angle to be in radians.
Of course, the parent tangent function is vertically expanded by a factor of 6 and horizontally expanded by a factor of 2.
