The probability that the train will be there when Alex arrives is 5/18
If Alex arrives at any time after 1.20pm the chances that train will be there is 1/3.
However if alex arrives at 1.00pm exactly there is no chance the train will be arrive there.
The probability that the train will be there increase linearly to 1/3 as alex's arrival time moves from 1.00pm to 1.20pm.
By arranging the probabilities over the first 20 minutes to get a 1/6 chance the train will be there if alex arrives between 1.00pm to 1.20pm
we get the final answer by
=1/3( 1/6 + 1/3 + 1/3)
=5/18
So, the probability that the train will be there when Alex arrives is 5/18
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Answer:
(1) 820
(2) 1920
Step-by-step explanation:
(1) solving 20 x 41, using associative property.
20 * 41 = (2 x 10) x 41 = 2 x (10 x 41)
= 20 x 41 = 2 x 410
= 820 = 820
(2) distribute 32 as 30 + 2 and solve.
60 x 32
= 60 x (30 + 2) = 60(30) + 60(2)
= 1800 + 120
= 1920
Two parallel lines never intersect, therefore they will never have a solution.
One line could be x=6 and the other could be x=2
Hope this helps :)
Answer:
Step-by-step explanation:
From the question we are told that:
Force 1 
Force 2 
Force 3 
Direction 1 
Direction 2 
Direction 3 
Generally Resolving forces to X axis is mathematically given by
Generally Resolving forces to Y axis is mathematically given by
Generally the equation for Resultant force R is mathematically given by
