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Bingel [31]
3 years ago
9

Which equation demonstrates the multiplicative identity property?

Mathematics
1 answer:
dedylja [7]3 years ago
5 0

Answer: Further explanation

There are several number operations that involve multiplication:

1. commutative

2. associative

3. closed

Multiplication between integers will produce integers too

4. distributive property

* addition

* substraction

5. identity

The multiplicative identity property is a multiplicative property in mathematics where each number multiplied by 1 will produce the original number or can be stated simply  :

"The product of any number and one is that number"

So The Multiplicative Identity is 1

can be stated in the formula:

From the available answer choices

a) (- 3 + 5i) + 0 = -3 + 5i

this is an addition operation and not multiplication while O is an identity in the sum operation, so the statement is false

b) (-3 + 5i) (1) = -3 + 5i

this is a multiplication operation and 1 is a Multiplicative Identity of multiplication, so the statement is true

c) (-3 + 5i) (-3 + 5i) = -16-30i

d) (-3 + 5i) (-3 + 5i) = 16 + 30i

choice c and is a multiplication factor, so the statement is false

Step-by-step explanation:

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Neko [114]
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4 0
3 years ago
Read 2 more answers
A major credit card company has determined that customers charge between $100 and $1100 per month. If the monthly amount charged
Alexxx [7]

Answer:

a) E(X) = \frac{a+b}{2} = \frac{100+1100}{2}=600

b) First we need to calculate the variance given by this formula:

Var(X) = \frac{(b-a)^2}{12}= \frac{(1100-100)^2}{12} = 83333.33

And the deviation would be:

Sd(X) = \sqrt{83333.33}= 288.675

c) P(600 < X< 889) = P(X

And using the cdf we got:

P(600 < X< 889)= F(889) -F(600) = \frac{889-100}{1000} -\frac{600-100}{1000}= 0.789- 0.5= 0.289

d) P(311 < X< 889)= F(889) -F(311) = \frac{889-100}{1000} -\frac{311-100}{1000}= 0.789- 0.211= 0.578

Step-by-step explanation:

For this case we define the random variable X who represent the customers charge, and the distribution for X on this case is:

X \sim Unif (a= 100,  b=1100)

Part a

For this case the average is given by the expected value and we can use the following formula:

E(X) = \frac{a+b}{2} = \frac{100+1100}{2}=600

Part b

First we need to calculate the variance given by this formula:

Var(X) = \frac{(b-a)^2}{12}= \frac{(1100-100)^2}{12} = 83333.33

And the deviation would be:

Sd(X) = \sqrt{83333.33}= 288.675

Part c

For this case we want to find the percent between 600 and 889, so we can use the cumulative distribution function given by:

F(x) = \frac{X -100}{1100-100}= \frac{x-100}{1000}, 100 \leq X \leq 1100

And we can find this probability:

P(600 < X< 889) = P(X

And using the cdf we got:

P(600 < X< 889)= F(889) -F(600) = \frac{889-100}{1000} -\frac{600-100}{1000}= 0.789- 0.5= 0.289

Part d

P(311 < X< 889) = P(X

And using the cdf we got:

P(311 < X< 889)= F(889) -F(311) = \frac{889-100}{1000} -\frac{311-100}{1000}= 0.789- 0.211= 0.578

6 0
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Lori makes 64,000 each year as a accountant at Christmas she was given a 12% bonus how much was her bonus
algol [13]

64000 x 0.12 = 7680

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Since the rectangle is a golden one, then the fraction:
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The correct answer is D then
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The answer is (147)= 7n+84
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