Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating
y=-2x^2-12x-28
a=-2
b=-12
xvalue of vertex is -(-12)/(2*-2)=12/-4=-3
x value of vertex is -3
plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10
yvalue is -10
x value is -3
vertex is (-3,-10)
\left[x \right] = \left[ 6\right][x]=[6] totally answer
Answer:
800
Step-by-step explanation:
8*10*10=
8*10=
80*10=
800cm.
i broke up the problem. hope this helps!
Y=3
Y=1.5x
If X=2 insert 2 into the equation
Y=1.5(2)
Y=3
4- 7x = 23- 5
4 - 7x = 18
-4 = -4
-7x = 14
/-7 = /-7
X = -2
3x = -6
