Answer:
0.0918
Step-by-step explanation:
We know that the average amount of money spent on entertainment is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The mean and standard deviation of average spending of sample size 25 are
μxbar=μ=95.25
σxbar=σ/√n=27.32/√25=27.32/5=5.464.
So, the average spending of a sample of 25 randomly-selected professors is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The z-score associated with average spending $102.5
Z=[Xbar-μxbar]/σxbar
Z=[102.5-95.25]/5.464
Z=7.25/5.464
Z=1.3269=1.33
We have to find P(Xbar>102.5).
P(Xbar>102.5)=P(Z>1.33)
P(Xbar>102.5)=P(0<Z<∞)-P(0<Z<1.33)
P(Xbar>102.5)=0.5-0.4082
P(Xbar>102.5)=0.0918.
Thus, the probability that the average spending of a sample of 25 randomly-selected professors will exceed $102.5 is 0.0918.
I honestly don't know, but I think it is 63
Answer: PART A : 
= 
PART B : 5.9 FEET
Step-by-step explanation:
Length of the first sign = 4.4 feet
height of the first sign = 3 feet
Length of the second sign = x feet
height of the second sign = 4 feet
If two shapes are similar , then the ratio of their sides are equal,
That is ;
= 
PART A
=
PART B
=
cross multiplying , we have
3x = 4.4 x 4
3x = 17.6
Divide through by 3
x = 17.6/3
x = 5.86666666666667
x≈ 5.9 feet
Therefore , the length of the new sign is 5.9 feet
Answer:
-t
Step-by-step explanation:
t - 5 - 2t + 5 =
t - 5 + 5 - 2t =
t - 2t =
-t
