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Zigmanuir [339]

3 years ago

7

∠A and ∠B are vertical angles. If ∠A=8x+14 and ∠B=2x+50, what is m∠B?

1 answer:

Maslowich3 years ago

4 0

Answer:

∠B = 62°

Step-by-step explanation:

Because ∠A and ∠B are vertical angles they are equal hence we can write

∠A = ∠B

8x + 14 = 2x + 50

Now we have to solve for x

To do so, subtract 2x on both sides of the equation:

6x + 14 = 50

Now, subtract 14 on both sides of the equation

6x = 36

Now, divide 6 on both sides of the equation

x = 6

To find m∠B you have to you have to plug in x = 6 back into the ∠B equation

∠B = 2(6) + 50

∠B = 62°

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Write the equation of a line perpendicular to y=-12x+2 going through (0,-1)

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$\rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}$

<em>Write the equation of a line perpendicular to y=-12x+2 going </em>

<em> through (0, -1)</em>

<em />

<em> </em> $\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}$

First, let's take a look at our provided information:-

A line $\text{y=-12x+2}$
A point (0, -1)
The line $\text{y=-12x+2}$ is perpendicular to the line that goes through (0, -1)

If two lines are perpendicular to each other, their slopes are opposite reciprocals of each other.

So we take the slope of the given line, which is -12, change its sign from minus to plus:-

$\Large\textit{12}$

And now, We flip the number over:-

$\Large\text{$\displaystyle\frac{1}{12}$}$

Now that we've found the slope of the line, let's find its equation.

The first step is to write it in point-slope form as follows:-

$\longmapsto\sf{y-y_1=m(x-x_1)}$

Replace letters with numbers,

$\longmapsto\sf{y-(-1)=\displaystyle\frac{1}{12}(x-0)}$

On simplification,

$\longmapsto\sf{y+1=\displaystyle\frac{1}{12} (x-0)}$

On further simplification,

$\longmapsto\sf{y+1=\displaystyle\frac{1}{12} x}$

Subtracting 1 on both sides,

$\longmapsto\sf{y=\displaystyle\frac{1}{12} x-1}$

$\Uparrow\texttt{Our equation in slope-intercept form}$

<h3>Good luck with your studies.</h3>

#TogetherWeGoFar

$\rule{300}{1}$

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