Answer:
D) Abner can spend $60 per month on school clothes and $20 per month on gym clothes and stay within his budget.
Step-by-step explanation:
In the problem it states that Abner will spend 3 times more on (s)school clothes than (g) gym clothes.
So it would appear as s ≥ 3g.
If we plug in $60 as s (school clothes) and $20 as g (gym clothes), the statement is true.
60 ≥ 3(20)
60 ≥ 60. These numbers make the linear system true.
If you have trouble with this, an easy way to find this answer is simply creating the linear system that represents the problem, (he will buy 3 times more school clothes than gym clothes) s ≥ 3g and plug in each variable from the answer choices until you find the variables that make the linear system true.
#2 #3 and #5 I think but I could be wrong. Good luck!
So elimination method is basically adding the equations and canceling out variables.
-6x + 6y = 6
-6x + 3y = -12
The eaiest way to solve is by multiplying the bottom equation by -1.
-6x + 6y = 6
6x - 3y = 12
Now you add the eqautions.
3y = 18
Divde 3 from both sides.
y = 6
Now plug in 6 into any of the original two equations. Lets use the first one.
-6x + 6(6) = 6
-6x + 36 = 6
Subtract 36 from both sides.
-6x = -30
Divide -6 from both sides.
x = 5
So your solution is (5, 6).
I hope this helps love! :)
The 4 functions are:
Let's keep in mind that for large values of x, a quadratic function grows faster than a linear function:
for large values of x
In this problem, we can see that the only quadratic function is
, while all the others are linear functions, so the function that grows faster for large values of x is
Answer: 70% is shaded. 7 are shaded and there is a total of 10. then you divide the answer would be 0.7 which is the same as 70%
Step-by-step explanation:
