Let the integers be x and x+1.
x = 6 + 2(x + 1)
x = 6 + 2x + 2
x = -8
Hence, the integers are -8 and -7.
Answer:
c
Step-by-step explanation:
because u cant be wrong with going with none of the above due the fact that they could be decimals and they didn't want to write out the full number therefore making it incorrect. No need to thank me.
Remember that the radicand (the area under the root sign) must be positive or zero for a radical with an even index (like the square root or fourth root, for example). This is because two numbers squared or to the fourth power, etc. cannot be negative, so there are no real solutions when the radicand is negative. We must restrict the domain of the square-root function.
If the domain has already been restricted to

, we can work backwards to add 11 to both sides. We see that

must be under the radicand, so the answer is
A.
Answer:
2a +2b +4
Step-by-step explanation:
The perimeter is the sum of the lengths of the three sides. If x represents the length of the third side, then ...
(3a +8) +(5a +b) +x = (10a +3b +12)
Subtracting from the equation everything on the left side that is not x, we get ...
x = (10a +3b +12) -(3a +8) -(5a +b)
= a(10 -3 -5) +b(3 -1) +(12 -8)
= 2a +2b +4
The length of the third side is 2a +2b +4.