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DedPeter [7]
3 years ago
7

Please answer if you know the right answer.(This is algebra)

Mathematics
1 answer:
Mkey [24]3 years ago
3 0
The answer is D

All you have to do is replace the C’s with 9 and see if the equation is right.
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Which values for x and y make the statement (x + 5)(y - 6) = 0 true?
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<span>                             ||Solving \ for \ x. ||  </span>

(x + 5)(y - 6) = 0 

(x + 5)(y - 6) = 0 :x

&#10;x+5=0&#10; &#10;  |Divide \ both \ sides \ by \ y-6| 

&#10;x=-5&#10; &#10;  |Subtract \ 5 \ from \ both \ sides|

                           ||Solving \ for \ y. || 

&#10;y-6=0&#10; &#10;  |Divide \ both \ sides \ by \ x+5| 
 
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Solution =\ \textgreater \ x = -5, y = 6
6 0
3 years ago
Can someone help me please​
sashaice [31]

Answer:

7/10

Step-by-step explanation:

I've attached an image on how you can use the diagram they gave you.

If you color in 7/10s and 7/12s you'll notice that 7/10s is greater.

This is because 1/10 of the whole is greater than 1/12 of the whole.

For 1/10, the whole is being divided into 10, so it equals 0.1.

On the other hand, in 1/12, the whole is being divided by 12, so a part equals 0.083

0.1 is greater than 0.083, so 7 of 0.1 is greater than 7 of 0.083

3 0
3 years ago
The sum of x and ten is twenty( write the equation
iren [92.7K]

Answer:

2x10=20 X=2

Step-by-step explanation:

Please mark brainliest

5 0
3 years ago
Read 2 more answers
Is this equation an identity?<br> -7 + 7g = -10 + 7g + 3
djverab [1.8K]

Answer: i dont really know if im right but here! :L

Step-by-step explanation: Now, say G is an Abelian group, finitely generated from generator In this sense abelian groups are “more interesting” than vector spaces. and in the table below, the second last column is the identity, while the last column is cyclic of order 4, with 9g the generator

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musickatia [10]
Replacement = 11 total

probability of choosing a consonant = 7/11
without replacing the card
probability of choosing an e = 3/10

probability of choosing both = 7/11 * 3/10 = 21/110 <===
8 0
3 years ago
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