Answer:
(1) 2 (2) (-1/2,0) (3) (0,1)
Step-by-step explanation:
The slope of the line is the number times x. This equation is y=mx+b, where m is the slope and b is the y-intercept. In this case, m is 2, so we have our slope. The y-intercept is easy, as we already know it to be (0,1). The x-intercept is the point where the line hits x when y=0. To solve for the x-intercept, we set y to 0 and solve. We have 0=2x+1. First, we subtract 1 from both sides and get -1=2x. Next, to get x by itself, divide both sides by 2. Now we have -1/2=x. Now we have our x coordinate for our x-intercept. Because of this, we get (-1/2,0) as our x-intercept.
Dont know,not sure of this one
Answer:
STEP 3
Step-by-step explanation:
Francesca drew point (–2, –10) on the terminal ray of angle , which is in standard position. She found values for the six trigonometric functions using the steps below.
A unit circle is shown. A ray intersects point (negative 2, negative 10) in quadrant 3. Theta is the angle formed by the ray and the x-axis in quadrant 1.
Francesca made her first error in step 3 because the sine, cosine, and tangent ratios are incorrect, which also resulted in incorrect cosecant, secant, and tangent functions.
please mark me brainlyest <i cant spell it >
Answer:
g(p)h(p) = = p^4 + 2p^3 - 8p^2 -2p + 4
Step-by-step explanation:
Hello!
We will use the distributive property:
g(p) h(p) = ( p - 2 ) * ( p^3 + 4p^2 - 2 ) = ( p^3 + 4p^2 - 2 ) * ( p - 2 )
The distributive property allow us to multiply the first term <em>(p^3 + 4p^2 - 2) </em>by every member of the second member, that is <em>p </em>and <em>-2.</em>
g(p) h(p) = ( p^3 + 4p^2 - 2 ) * p + ( p^3 + 4p^2 - 2 ) * (-2)
Now we can do the same for the two resulting terms, that is, we can multiply every term in parenthesis<em> ( p^3 + 4p^2 - 2 ) </em>by the term on the rigth:
( p^3 + 4p^2 - 2 ) * p = (p^3)*p + (4p^2)*p - 2*p = p^4 + 4p^3 -2p
( p^3 + 4p^2 - 2 ) * (-2) = (p^3)*(-2) + (4p^2)*(-2)- 2*(-2) = -2p^3 - 8p^2 + 4
And now we can sum both terms and add monomials with the same exponent of t. Look at the underlined terms
g(p) h(p) = p^4 + <em><u>4p^3</u></em><em> </em>-2p - <u>2p^3 </u>- 8p^2 + 4 = p^4 +<em><u>2p^3</u></em> -2p - 8p^2 + 4
= p^4 + 2p^3 - 8p^2 -2p + 4
