3 years ago

Help evaluating the question

Mathematics

2 answers:

serg [7]3 years ago

5 0

X=1 so it is 1×1×1=1 so.... it is 19+1

____ [38]3 years ago

5 0

Z + x^3
19 + 1^3
19 + 1= 20

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Licemer1 [7]

Near the point (6, 6, 3), we have the approximation

$f(x,y,z)\approx f(6,6,3)+f_x(6,6,3)(x-6)+f_y(6,6,3)(y-6)+f_z(6,6,3)(z-3)$

where the subscripted $f$ 's refer to the corresponding partial derivatives.

$f(x,y,z)=x^2+y^2+z^2$
$\implies\begin{cases}f_x(x,y,z)=2x\\f_y(x,y,z)=2y\\f_z(x,y,z)=2z\end{cases}$

So

$f(6.02,5.97,2.99)\approx80.8288$

Compare to more precise value,

$f(6.02,5.97,2.99)\approx80.8214$

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4 years ago

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Aneli [31]

Answer:

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