2 years ago

Help evaluating the question

Mathematics

2 answers:

serg [7]2 years ago

5 0

X=1 so it is 1×1×1=1 so.... it is 19+1

____ [38]2 years ago

5 0

Z + x^3
19 + 1^3
19 + 1= 20

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Eliminate the parameter t. Then use the rectangular equation to sketch the plane curve represented by the given parametric equat

____ [38]

Answer:

$9x^2+4y^2=36$

Step-by-step explanation:

We are given that

$x=2cos t$

$y=3 sin t$

$0\leq t\leq 2\pi$

$cost=\frac{x}{2}$

$sint=\frac{y}{3}$

$sin^2 t+cos^2 t=(\frac{x}{2})^2+(\frac{y}{3})^2$

$1=\frac{x^2}{4}+\frac{y^2}{9}$

By using the formula

$sin^2\theta+cos^2\theta=1$

$1=\frac{9x^2+4y^2}{36}$

$9x^2+4y^2=36$

4 0

2 years ago

Expand and simplify (x+5)(x-2)

neonofarm [45]

Answer:

${x}^{2} + 3x - 10$

Step-by-step explanation:

$(x + 5)(x - 2)$

utilise the Foil method to expand brackets:

F - mulply the first terms (x and x)

O - multiply the outside terms ( x and -2)

I - multiply the inside terms (5 and x)

L - multiply the last terms (5 and -2)

Then add them as following:

${x}^{2} - 2x + 5x - 10$

Then combine like terms:

${x}^{2} + 3x - 10$

6 0

3 years ago

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If a = -5, then 2a = -10<br> what is the property

Stolb23 [73]

Answer:

There would be no property because it doesn't form any conic sections.

Hope this helped :)

P.S. Are there answer choices?

6 0

2 years ago

if the radius of a sphere is tripled, the surface area of a sphere will increasea) by a factor of 3b) by a factor of 4c)by a fac

Vlad1618 [11]

Answer:

Step-by-step explanation:

The area and the radius of a sphere are related by the formula:

A=4πr^2

Let’s say this is A1 and r1

Now the radius is tripled. This means r2 = 3r1

The new area thus becomes: A = 4 * (3r)^2 * π = 36πr^2

Comparing A1 and A2 , we can see that A2 = 9A1

4 0

3 years ago

What is <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B5%7D%20" id="TexFormula1" title=" \frac{3}{5} " alt=" \frac{3}

Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

3/5 * 15

Rewriting as

3 * 15/5

3 * 3

3 0

2 years ago

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