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umka21 [38]
2 years ago
9

Jim wants to put a wallpaper border around a rectangular room. The

Mathematics
2 answers:
Mariana [72]2 years ago
8 0

Answer:

Perimeter is distance around the room.

Perimeter = 14 + 10 +14 +10 = 48 feet

Rolls needed = Perimeter / roll length = 48 /20 = 2.4.

Since you can't buy a partial roll you have to get a full roll

Rolls need = 2.4 rounded up to the next number is 3.

Answer is C.

Step-by-step explanation:

puteri [66]2 years ago
5 0

Answer:3

Step-by-step explanation:

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Yolanda drove 605 miles in 11 hours. At the same rate, how many miles would she drive in 5 hours?
aalyn [17]

Answer:

275 miles

Step-by-step explanation:

Divide 605/11 to find out the rate.

Rate is 55 miles per hour.

5 * 55 = 275 miles

6 0
1 year ago
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The graph of the line y= 3 is a line that has which of the following characteristics?
vaieri [72.5K]

Answer:

21

Step-by-step explanation:

4 0
2 years ago
Avani is building a rectangular play area. The length of the play area is 7.5 meters. The width of the play area is 5.3 meters.
MakcuM [25]
The area equals length time width so 7.5 times 5.3 = 39.75.
5 0
3 years ago
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Mr. Smith is flying his single-engine plane at an altitude of 2400 feet. He sees a cornfield at an angle of depression of 30º. W
Svet_ta [14]

Answer:

Height of the fighter plane =1.5km=1500 m

Speed of the fighter plane, v=720km/h=200 m/s

Let be the angle with the vertical so that the shell hits the plane. The situation is shown in the given figure.

Muzzle velocity of the gun, u=600 m/s

Time taken by the shell to hit the plane =t

Horizontal distance travelled by the shell =u

x

t

Distance travelled by the plane =vt

The shell hits the plane. Hence, these two distances must be equal.

u

x

t=vt

u Sin θ=v

Sin θ=v/u

=200/600=1/3=0.33

θ=Sin

−1

(0.33)=19.50

In order to avoid being hit by the shell, the pilot must fly the plane at an altitude (H) higher than the maximum height achieved by the shell for any angle of launch.

H

max

=u

2

sin

2

(90−θ)/2g=600

2

/(2×10)=16km

4 0
2 years ago
What is the average rate of change from x = −3 to x = −4?
Vika [28.1K]

Answer:

-2

Step-by-step explanation:

Since it would be immensely helpful to know the equation of this parabola, we need to figure it out before we can continue.  We have the work form of a positive upwards-opening parabola as

y=a(x-h)^2+k

where a is the leading coefficient that determines the steepness of lack thereof of the parabola, x and y are coordinates of a point on the graph, and h and k are the coordinates of the vertex.  We know the vertex: V(-3, -3), and it looks like the graph goes through the point P(-2, -1).  Now we will fill in the work form equation and solve for a:

-1=a(-2-(-3))^2-3

which simplifies a bit to

-1=a(1)^2-3

and

-1 = a(1) - 3.  Therefore, a = 2 and our parabola is

y=2(x+3)^2-3

Now that know the equation, we can find the value of y when x = -3 (which is already given in the vertex) and the value of y when x = -4.  Do this by subbing in the values of x one at a time to find y.  When x = -3, y = -3 so the coordinate of that point (aka the vertex) is (-3, -3).  When x = -4, y = -1 so the coordinate of that point is (-4, -1).  The average rate of change between those 2 points is also the slope of the line between those 2 points, so we will use the slope formula to find it:

m=\frac{-1-(-3)}{-4-(-3)} =\frac{2}{-1}=-2

And there you have it!  I'm very surprised that this question sat unanswered for so very long!  I'm sorry I didn't see it earlier!

5 0
2 years ago
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