Solve for y<br> 7y

kap26 [50]

Here is a quadratic equation x^2 + 5x = 14
x^2 + 5x - 14 = 0 - Subtract 14 from both sides
(x + 7)(x - 2) = 0 - Factor
x + 7 = 0 x - 2 = 0 - Set each factor equal to 0
x = -7 x = 2 - solve each piece

If the constant is easy to find factors of then use the factoring method
If the constant is difficult and you have a graphing calculator, then graph
If no graphing calculator then use the quadratic formula

7 0

3 years ago

What is the perimeter of the kite?<br> a.44<br> b.140

Andreyy89

Answer:

B.) 140 is your answer for your problem

5 0

2 years ago

The admission fee at an amusement park is 20$ for children and 35$ adults. On a certain, day 264 people entered the park, and th

shtirl [24]

Answer:

100 Adults and 164 Children

Step-by-step explanation:

To solve this we will need to write two equations to solve for the two unknowns. Firstly, we know that tickets are 20 for children and 35 for adults, and that the total price was 6780. We can write an expression to represent this. 6780 is the total price, this also means it is the price of all the adults + the price of all the children. The total price of the adults tickets is the price of each ticket multiplied by the number of adults, so the total price of adult tickets can be represented by: 35A, 35 being the ticket price per adult, and A being the number of adults. Similarly the total children's price can be expressed as such: 20C, 20 being the price per child, and C being the number of children. Since we know that these two values total to 6780, we can now form an equation:

35A (total adult price) + 20C (total children price) = 6780

35A+20C=6780

Now we need another expression so we can substitute for one of the values. The other piece of information we are given, is that a total of 264 people entered the park. This means that the total number of adults + the total number of children = 264. Since we already have variables for the numbers of adults and children we now have our second equation:

A (number of adults) + C (number of children) = 264

A+C=264

Now we can use this second equation to substitute for one of the values in the first equation. Let's substitute for children:

If we rearrange the second expression we will get:

A+C-A=264-A

C=264-A

So now we substitute this expression into our first formula:

35A+20C=6780

C=264-A

35A+20(264-A)=6780

Now since we only have one unknown, we can simplify, expand and solve!

35A+20*264-20*A=6780

35A+5280-20A=6780

35A-20A+5280-5280=6780-5280

15A=1500

15A/15=1500/15

A= 100

A total of 100 adults were admitted.

Now we can use the number of adults to find the number of children using our second formula:

C=264-A

C=264-100

C=164

And there we are! A total of 100 adults and 164 children were admitted.

Hope this helped!

4 0

3 years ago

En el estante de un negocio hay 2 tipos de tarros de la misma mermelada y marca. El tarro más alto tiene el doble de altura que

Ipatiy [6.2K]

Answer:

tarro corto

Step-by-step explanation:

Aquí tenemos que comprar el frasco que tiene el menor costo por volumen.

$h_1$ = Altura del frasco corto

$h_2$ = La altura del frasco alto es el doble que el del frasco corto. = $2h_1$

$d_1$ = Diámetro del frasco corto

$d_2$ = El diámetro del frasco alto es la mitad del frasco corto = $\dfrac{1}{2}d_1$

El volumen de un cilindro es $\pi \dfrac{d^2}{4}h$

La razón de los volúmenes de los frascos es

$\dfrac{V_1}{V_2}=\dfrac{\pi\dfrac{d_1^2}{4}h_1}{\pi\dfrac{d_2^2}{4}h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{d_2^2h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{(\dfrac{1}{2}d_1)^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{\dfrac{1}{4}d_1^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{1}{\dfrac{1}{2}}\\\Rightarrow \dfrac{V_1}{V_2}=2\\\Rightarrow V_1=2V_2$

El costo del frasco corto por unidad de volumen es

$\dfrac{8000}{V_1}=\dfrac{8000}{2V_2}=\dfrac{4000}{V_2}$

El costo del frasco alto por unidad de volumen es

$\dfrac{4500}{V_2}=\dfrac{4500}{V_2}$

$\dfrac{4000}{V_2}$

Entonces, el costo del frasco corto por unidad de volumen es menor que el costo por unidad de volumen del frasco alto.

Por lo tanto, deberíamos tomar el frasco corto.

5 0

3 years ago

Two wheels rolled simultaneously. The radius of the smaller wheel is r feet and the radius of the larger wheel is 2r feet If bot

Mnenie [13.5K]

The smaller wheel rolled
.. 4*2πr = 8πr . . . . feet

The larger wheel rolled
.. 4*2π*2r = 16πr . . feet

The larger wheel traveled (16πr -8πr) = 8πr feet farther than the small wheel.

6 0

3 years ago

Solve for y 7y - 8 = 41