Step-by-step explanation:
A.
Null hypothesis
H0: σ1² ≤ σ2²
Alternative hypothesis
H1: σ1² > σ2²
We have level of significance = 0.01
Test statistic
F = S1²/S2²
= 170²/100²
= 28900/10000
F = 2.89
Df = degrees of freedom
Df1 = n1 - 1
= 26-1
= 25
Df2 = n2 - 1
= 25-1
= 24
B. We get the p value using f distribution
Fdist(2.89,25,24)
P value = 0.0057
The p-value is less than 0.01 so we reject null hypothesis.
So we conclude that automobiles that are of 4 years have their variances to be larger In annual repair costs than those that are of 2 years.
Reasonableness: we expect this since 4byears old automobiles are more likely to have more expenses during repair leading to greater variances
(i) The scale factor is 6 because of the ratio between the 2 given corresponding sides.
I don't know the second part, but I hope this helps regardless.
25 because you do 19 squared plus 16 squared equals 617, you do 617 rooted. It’s called pythagorus.
5/1 x 6 4/15
5/1 x 94/15
Answer: 94/3 or 31 1/3
Your answer would be D because you are multiplying $0.59 by the number of pounds there are.