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emmasim [6.3K]
3 years ago
5

Find the gradients of the lines A and B. a) Gradient of A is __ b) Gradient of B is __

Mathematics
1 answer:
Shkiper50 [21]3 years ago
6 0

Answer:

Kkķķkkkkkkkkkkkkkk

Step-by-step explanation:

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-3(4x+3)+4(6x+1)=43 how do I solve it
Gala2k [10]
Solve for x:
4 (6 x + 1) - 3 (4 x + 3) = 43
-3 (4 x + 3) = -12 x - 9:
-12 x - 9 + 4 (6 x + 1) = 43
4 (6 x + 1) = 24 x + 4:
24 x + 4 - 12 x - 9 = 43
Grouping like terms, 24 x - 12 x - 9 + 4 = (24 x - 12 x) + (4 - 9):
(24 x - 12 x) + (4 - 9) = 43
24 x - 12 x = 12 x:
12 x + (4 - 9) = 43
4 - 9 = -5:
12 x + -5 = 43
Add 5 to both sides:
12 x + (5 - 5) = 5 + 43
5 - 5 = 0:
12 x = 43 + 5
43 + 5 = 48:
12 x = 48
Divide both sides of 12 x = 48 by 12:
(12 x)/12 = 48/12
12/12 = 1:
x = 48/12
The gcd of 48 and 12 is 12, so 48/12 = (12×4)/(12×1) = 12/12×4 = 4:
Answer:  x = 4
3 0
4 years ago
A LITTLE HELP PLEASE!! Find the area of this regular polygon. Round to the nearest tenth.
dem82 [27]

rounding to the nearest tenth will be 20

7 0
3 years ago
Martina is currently 12 years older than her cousin Joey. In 4 years she will be 3 times as old
Katarina [22]

\Huge{\underline{\underline{\sf{\red{AnSwEr:}}}}}

\boxed{\sf{Martina's \: Present \: age = 14 \: years}}

\boxed{\sf{Her \: cousin's \: Present \: age = 2\: years}}

\Huge{\underline{\underline{\sf{\green{ExpLaNaTion:}}}}}

= Let Martina's cousin's age be = n

= Let her age be = n+12

After four years,

Cousin's age = n+4

Her age = n+12+4=n+16

But according to the question her age = 3(n+4) = 3n+12

Thus,

3n+12=n+16

3n-n=16-12

2n=4

n=4/2

\boxed{ \sf {n = 2}}

Thus ,

Her cousin's present age = n = 2

Her cousin's present age = n = 2Her present age = n+12 = 2+12=14

5 0
3 years ago
What is 0.94 in centimeters​
tankabanditka [31]

assuming that 0.94 is in inches, in centimeters its 2.3876

6 0
3 years ago
Read 2 more answers
Can somebody please help me with this
enot [183]

Step-by-step explanation:

  • 1

x²-8x+15= 0

x²-2*1*4*x+ 16-1=0

x²-2*1*4*x+4² = 1

(x-4)² = 1

x-4 =1   or x-4= -1

x= 5      or x=3

so the solutions are 5 and 3

  • 2

r²+18r+56=0

r²+2*1*9*r+ 81-25=0

r²+2*1*9*r+9² = 25

(r+9)² = 25

r+9 = 5  or r+9 = -5

r= -4  or   r = -14

so the solutions are -4 and -14

  • 3

x²+2x-24=0

x²+2*1x +1-25=0

x²+2*1*x+1² = 25

(x+1)² = 25

x+1= 5  or x+1= -5

x = 4 or   x= -6

so the solutions are 4 and -6

  • 4

p²+12p-54 = 0

p²+2*6*p+36-90=0

p²+2*6*p+6² = 90

(p+6)² = 90

p+6 = √90 or p+6 = -√90

p = √90-6  or p=  -√90-6

  • 5

m²-6m-55= 0

m²-2*3*m+3²-64=0

(m-3)² = 64

m-3 = 8 or m-3 = -8

m= 11 or m= -5

4 0
3 years ago
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