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Lapatulllka [165]
3 years ago
5

Write the equation of the line that passes through

Mathematics
1 answer:
Tom [10]3 years ago
7 0

Answer:

y=63x+65

Step-by-step explanation:

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11/20 as a simplified fraction
NikAS [45]
Fraction already reduced simplified to lowest terms gcf ( 11/20 ) =1 numerator and denominator are coprime number they no common prime factors.
5 0
3 years ago
Use the algebraic procedure explained in section 8.9 in your book to find the derivative of f(x)=1/x. Use h for the small number
Triss [41]

Answer:

By definition, the derivative of f(x) is

lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}

Let's use the definition for f(x)=\frac{1}{x}

lim_{h\rightarrow 0} \frac{\frac{1}{x+h}-\frac{1}{x}}{h}=\\lim_{h\rightarrow 0} \frac{\frac{x-(x+h)}{x(x+h)}}{h}=\\lim_{h\rightarrow 0} \frac{\frac{(-1)h}{x^2+xh}}{h}=\\lim_{h\rightarrow 0} \frac{(-1)h}{h(x^2+xh)}=\\lim_{h\rightarrow 0} \frac{-1}{x^2+xh)}=\frac{-1}{x^2+x*0}=\frac{-1}{x^2}

Then, f'(x)=\frac{-1}{x^2}

7 0
4 years ago
What is the least common denominator of 9,8,6,5
Alex

Answer:

1

Step-by-step explanation:

LCD = 1

Equivalent Fractions with the LCD

9 = 9/1

8 = 8/1

6 = 6/1

5 = 5/1

Solution:

Rewriting input as fractions if necessary:

9/1, 8/1, 6/1, 5/1

For the denominators (1, 1, 1, 1) the least common multiple (LCM) is 1.

LCM(1, 1, 1, 1)

Therefore, the least common denominator (LCD) is 1.

Calculations to rewrite the original inputs as equivalent fractions with the LCD:

9 = 9/1 × 1/1 = 9/1

8 = 8/1 × 1/1 = 8/1

6 = 6/1 × 1/1 = 6/1

5 = 5/1 × 1/1 = 5/1

4 0
4 years ago
Solve.
horrorfan [7]
.hello : 
<span>2d−e=7....(1)
d+e=5.....(2)
(1)+(2) : 3d=12
d=4
subsct in (2) : 
4+e=5
e=1
conclusion : 
</span><span>The solution is (4, 1).</span><span>

</span>
4 0
3 years ago
Read 2 more answers
Find the HCF of<br> x^4 y^2 and x^3 y^3
forsale [732]

Here's your answer down here↓:

Step-by-step explanation:

x^3 - y^3 = (x - y)(x^2 + xy + y^2)

(x^4 - y^4) = (x^2 - y^2)(x^2 + y^2) = (x - y)(x + y)(x^2 + y^2)

Ok. So the factor (x-y) appears once in the top line and once in the second line. So we are going to take it the least amount of times.

So, the factor (x + y) appears in the top line zero times and in the second line one time so we will take it where it appears the least which is zero times so we are still at (x - y)

And it Same goes for the factors of (x^2 + y^2) and (x^2 + xy + y^2)

8 0
2 years ago
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