Answer:
The compound which are boh soluble in water and hexane is
B. Ethanol and 1-propanol
Explanation:
The compounds ethanol and 1-propanol are soluble in both hexane and water.
It is soluble in water as both consists of polar end due to hydrogen bonding present in the -OH functional group.
and both are soluble in hexane as they contain a non polar end and the alliphatic hydrocarbon chain in them.
The solubility of alcohols varies in increasing order as the hydrocarbon chain increases. And becaue of this it becomes more non polar.
Non polar properties decreases for branched molecules.
so, the correct option is ethanol and 1-propanol.
Answer:
Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation.
Explanation:
The benzene ring in itself does not easily undergo electrophilic substitution reaction. Some groups activate or deactivate the benzene ring towards electrophilic substitution reactions.
-NO2 ia a highly deactivating substituent therefore, Friedel-Crafts alkylation of nitrobenzene does not take place under any conditions.
This reaction scheme is therefore flawed because Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation.
Idk it’s making me answer a question in order to get help on my own
To make 1 Molar solution of hemoglobin ; 1600 grams of hemoglobin will be dissolved in 1 liter of water
The molecular weight of Hemoglobin is approximately 16,000 Daltons, when hemoglobin is converted to mM
16000 Dalton = 16000 ( g/mol )
given that 1 Dalton = 1 g/mol
To make 1 molar solution of hemoglobin using 1 liter of water
1 liter = 1000 grams
16000 Dalton = 16000 g/mol
Hence 16,000 grams of Hemoglobin is required to make 1 Molar solution of hemoglobin using 1 liter of water.
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Answer:
1.1 M
General Formulas and Concepts:
- Molarity = moles of solute / liters of solution
Explanation:
<u>Step 1: Define variables</u>
1.2 mol KCL
1.1 L of solution
M = unknown
<u>Step 2: Solve for Molarity</u>
- Substitute: M = 1.2 mol/1.1 L
- Evaluate: M = 1.09091
<u>Step 3: Check</u>
<em>We are given 2 sig figs. Follow sig fig rules.</em>
1.09091 M ≈ 1.1 M