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timama [110]
3 years ago
6

Equal amounts of N2 and O2 are added, under certain conditions, to a closed container. Which changes occur in the reverse reacti

on as the system proceeds toward equilibrium
Chemistry
1 answer:
geniusboy [140]3 years ago
4 0
1) The forward reaction is N2 (g) + O2 (g)  → 2NO

(that reaction requires special contitions because at normal pressures and temperatures N2 and O2 do not react to form another compound.

2) The equiblibrium equation is

  N2 (g) + O2 (g)  ⇄ 2NO

3) Then, the reverse reaction is

2NO → N2(g) + O2(g)

Answer: 2NO → N2(g) + O2(g)
You might be interested in
Select the following statements that are true. Select all that apply.
geniusboy [140]

Answer:

The statements which are true among these are: (a),(b) and (c) because,

(a) The simplest organic compounds which contains only carbon and hydrogen atoms are called hydrocarbons.

(b) The IUPAC naming of organic compounds have some rules for the naming of compounds, which consists of

  • Finding the longest chain present in the compound called parent chain.
  • A prefix for any substituent attach to the parent chain.

And lastly a suffix for the type of bond that molecule have.

(c) Isomers are the compound which same same molecular formula but different arrangement of molecules, due to this different arrangement they have different physical and chemical properties.

4 0
4 years ago
A compound of a transition metal and iodine is 56.7% metal by mass.How many grams of the metal can be obtained from 630 g of thi
erma4kov [3.2K]

Answer:

357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine

Explanation:

In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.

Given mass of sample compound = 630 g

Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;

56.7 % = 56.7/100 = 0.567

Mass of transition metal = 0.567 * 630 = 357.21 g

Therefore, the mass of the transition metal  present in 630 g of the compound is approximately 357 g

4 0
3 years ago
Consider the reaction 2Al + 6HBr → 2AlBr3 + 3H2. If 8 moles of Al react with 8 moles of HBr, what is the limiting reactant?
TiliK225 [7]

Answer:- HBr is limiting reactant.

Solution:- The given balanced equation is:

2Al+6HBr\rightarrow 2AlBr_3+3H_2

From this equation, There is 2:6 mol or 1:3 mol ratio between Al and HBr. Since we have 8 moles of each, HBr is the limiting reactant as we need 3 moles of HBr for each mol of Al.

The calculations could be shown as:

8molAl(\frac{6molHBr}{2molAl})

= 24 mol HBr

From calculations, 24 moles of HBr are required to react completely with 8 moles of Al but only 8 moles of it are available. It clearly indicates, HBr is limiting reactant.

7 0
3 years ago
When molecules are joined I an ordered structure​
olga2289 [7]

Answer:

ice

Explanation:

5 0
3 years ago
Write the balanced equation for a reaction between aqueous nitric acid (HNO3) and solid lithium metal (this is a single replacem
Lemur [1.5K]

<u>Answer:</u> The equation is given below.

<u>Explanation:</u>

Single replacement reactions are the chemical reactions in which more reactive metal displaces a less reactive metal from its chemical reaction. General equation for these reactions is given by the equation:

A+BC\rightarrow AC+B

Metal A is more reactive than metal B.

The reactivity of metals is judged with the help of reactivity series. In this series, the metals lying above are more reactive than the metals which lie below in the series.

For the reaction of solid lithium metal and nitric acid, the equation follows:

3Li(s)+4HNO_3(aq.)\rightarrow 3LiNO_3(aq.)+2H_2O(l)+NO(g)

This is a type of single replacement reaction because Lithium (more reactive metal) is replacing Hydrogen (less reactive metal) from the chemical reaction.

3 0
3 years ago
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