Answer:
Area is = to 1017.88
Circumference is = to 113.1
Step-by-step explanation:
To find the area of a circle use the formula A=πr2
So . . .
A = π18²
A = π324
A = 1017.88
To find the circumfrence of a circle use formula C=2πr
So . . .
C = 2π18
C= 113.1
Hope this helps
Brainliest please!
Answer:
beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans
The complete question is
Three tennis balls are stored in a cylindrical container with a height of 8 inches and a radius of 1.43 inches. The circumference of a tennis ball is 8 inches. a) Find the volume of a tennis ball b) There are 3 tennis ball in the container Find the amount of space within the cylinder not taken up by the tennis balls. Round your answers to the nearest hundredth.
Part a)
we know that
length of a circumference=2*pi*r----------> r=length/(2*pi)---> 8/(2*pi)
r=1.27 in------> radius of tennis ball
volume of a tennis ball is equals to the volume of a sphere
[volume of a sphere]=(4/3)*pi*r³----> (4/3)*pi*1.27³---> 8.58 in³
the answer Part a) is
the volume of a tennis ball is 8.58 in³
Part b)
[volume of the container]=pi*r²*h-----> pi*1.43²*8----> 51.39 in³
[volume of 3 tennis balls]=8.58*3-----> 25.74 in³
the amount of space within the cylinder not taken up by the tennis balls is
51.39-25.74-----> 25.65 in³
the answer Part b) is
25.65 in³
Answer:
6
Step-by-step explanation:
Answer is there the value of this
<h3>
Answer: x-3</h3>
Since p(3) = 0, this means x = 3 plugs into p(x) to get 0
We can write p(x) as p(x) = (x-3)q(x) where q(x) is some other polynomial that multiplies with (x-3) to lead to x^3-3x^2-x+3
Let's plug in x = 3 and see what happens
p(x) = (x-3)q(x)
p(3) = (3-3)q(3)
p(3) = 0*q(3)
p(3) = 0
No matter what the result of q(3) was, it doesn't matter because it multiplies with 0 to get 0.
The general rule is: if p(k) = 0, then x-k is a factor of p(x). This is a special case of the remainder theorem.
