Answer:
5 english students in each team
Step-by-step explanation:
So there are multiple ways to do this, you could do trial and error or you could factor out common numbers between the two.
Through trial and error, the lowest possible number of groups that could be divided between the number of students whilst still being able to maintain a whole # was 16 groups
- 128 math students ÷16 groups = 8 math students/group
- 80 english students ÷ 16 groups = 5 english students/group
The other way to solve this is to factor out common numbers between the two:
Yes, because it could maintain the flow of traffic efficiency. It would lessen the chances of car accidents because it would leave less room for user error
Answer:
4(-6), 6(-4), 12(-2)
Step-by-step explanation:
-4(6) = -4 x 6 = -24
so
4(-6) = 4 x -6 = -24
6(-4) = 6 x -4 = -24
12(-2) = 12 x -2 = -24
Answer:
Add 7 black beads
Step-by-step explanation:
Since we can only change the number of black beads, decide how many black beads you will add based on how many white beads there are.
There are three white beads in the picture.
Total beads we will have (<em>b</em> meaning black) b : 3
Ratio black : white beads 3 : 1
Use the common ratio, which is a number that both sides of the original ratio multiply by to get to the new ratio.
Find common ratio by dividing total by ratio white beads: 3/1 = 3
Multiply ratio black beads by common ratio. 3 X 3 = 9
<u>We need 9 black beads in total</u>.
Check answer
9 : 3 Both sides divisible by 3; reduce ratio
= 3 : 1 Correct ratio
There will be a total of 9 black beads, but we already have 2 black beads:
(9 total) - (2 original) = (7 to add)
Therefore we need to add 7 black beads.
