Anything with a zero denominator is undefined.
No x = -10 cannot be an input value because the x is the number of students , which can only be from 0 and above. You cannot have negative students.
Answer:
Area of shape = 187 cm²
Step-by-step explanation:
Given:
Length of rectangle = 15 cm
Width of rectangle = 9 cm
Height of triangle = (22-9) cm = 13 cm
Base of triangle = (15-7) cm = 8 cm
Find:
Area of shape
Computation:
Area of shape = Area of rectangle + Area of triangle
Area of shape = (l)(b) + (1/2)(b)(h)
Area of shape = (15)(9) + (1/2)(8)(13)
Area of shape = 135 + 52
Area of shape = 187 cm²
A = bh
b = 4h
A = 324
324 = 4h * h
324 = 4h^2
324/4 = h^2
81 = h^2
sqrt 81 = h
9 = h
b = 4h
b = 4(9)
b = 36
so the height (h) = 9 cm and the base (b) = 36 cm
Answer:
x1=-4/5, x2=18/5 and x3=7/5
Step-by-step explanation:
![\left[\begin{array}{ccc|c}1&0&-3&-5\\3&1&2&4\\2&2&1&7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%260%26-3%26-5%5C%5C3%261%262%264%5C%5C2%262%261%267%5Cend%7Barray%7D%5Cright%5D)
you can do linear combination between the rows:
2nd row=R2-3R1 and 3th row=R3-2R1
![\left[\begin{array}{ccc|c}1&0&-3&-5\\0&1&11&19\\0&2&7&17\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%260%26-3%26-5%5C%5C0%261%2611%2619%5C%5C0%262%267%2617%5Cend%7Barray%7D%5Cright%5D)
3th row=(3R2-R3)/15
![\left[\begin{array}{ccc|c}1&0&-3&-5\\0&1&11&19\\0&0&1&\frac{7}{5} \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%260%26-3%26-5%5C%5C0%261%2611%2619%5C%5C0%260%261%26%5Cfrac%7B7%7D%7B5%7D%20%5Cend%7Barray%7D%5Cright%5D)
1st row=R1+3R3 and R2-11R3
![\left[\begin{array}{ccc|c}1&0&0&-4/5 \\0&1&0&18/5 \\0&0&1&7/5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%260%260%26-4%2F5%20%5C%5C0%261%260%2618%2F5%20%5C%5C0%260%261%267%2F5%5Cend%7Barray%7D%5Cright%5D)
x1=-4/5, x2=18/5 and x3=7/5
