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STALIN [3.7K]
3 years ago
11

Find the least common multiple of 14 and 6. Answer:

Mathematics
2 answers:
Oksanka [162]3 years ago
5 0

Answer:

42

Step-by-step explanation:

First I multiplied 14 by 6, obtaining 84.  Next, I divided that by 2, obtaining 42.  This 42 is evenly divisible by both 14 and 6.  Thus, the LCM is 42.

Anna [14]3 years ago
5 0
Your answer would be 42
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Carolina has built her dog bed that is 2 1/8 feet wide and 5 1/3 feet long. Find the area of the bed
Brilliant_brown [7]

Answer:

The answer would be 11 1/3 ft sqared

4 0
2 years ago
Jennifer is making bouquets of flowers. She has 25 roses, 45 tulips, and 15 snapdragons. She divides the flowers equally to make
chubhunter [2.5K]

Answer:

a. 3

Step-by-step explanation:

The number of flowers should be divisible by the number of bouquets.

Since

25 = 5 \times 5 \\ 45 = 5 \times 9 \\ 15 = 5 \times 3

there should be 5 bouquets, and each bouquet has 5 roses, 9 tulips and 3 snapdragons.

so the answer is

a. 3

8 0
3 years ago
Read 2 more answers
What is the twentieth term of the arithmetic sequence described by the<br> equation an= 3n - 10?
sergij07 [2.7K]

Answer:

The twentieth term is 50.

Step-by-step explanation:

The equation that describes the arithmetic sequence describes it's "general term", which means that all the numbers in that sequence must follow that equation. For instance, if we want to find the first term of the sequence we must make a = 1 and we have:

a1 = 3*1 - 10

a1 = -7

Therefore to find the twentieth term we need to make n equal to 20. This is done below:

a20 = 3*20 - 10

a20 = 60 - 10

a20 = 50

The twentieth term is 50.

8 0
3 years ago
Please help #12 10 points
eimsori [14]
1. add 40 to the 40 and 25
2. now you have
\frac{5x {}^{2} }{5}   = \frac{65}{5}
3. then you have
{x}^{2}  = 13
4. then square root
{x}^{2}  = 13
5.then round answer to nearest tenth which is
x = 3.61
3 0
3 years ago
What is the range of y = sinx in the interval - π ≤ x ≤ 0?
Kaylis [27]

Answer:

-1 \le y \le 1

Step-by-step explanation:

Let be y = \sin x, the range of the function corresponds to the set of values of y. The sine function is a bounded function between -1 and 1. Hence, the range of the function is:

-1 \le y \le 1

6 0
2 years ago
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