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STALIN [3.7K]
4 years ago
11

Find the least common multiple of 14 and 6. Answer:

Mathematics
2 answers:
Oksanka [162]4 years ago
5 0

Answer:

42

Step-by-step explanation:

First I multiplied 14 by 6, obtaining 84.  Next, I divided that by 2, obtaining 42.  This 42 is evenly divisible by both 14 and 6.  Thus, the LCM is 42.

Anna [14]4 years ago
5 0
Your answer would be 42
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Two airplanes are carrying food and medical supplies to a country in need. One airplane is carrying 63 meals and 57 medical kits
Tju [1.3M]

Answer:

63m + 57k = 714 ____________ (1)

78m + 57k = 789 ____________(2)

The price of one meal is $5

Step-by-step explanation:

Let the price of one meal be m.

Let the price of one medical kit be k.

One airplane is carrying 63 meals and 57 medical kits and the total cost for those supplies on that airplane is $714.

This means that:

63m + 57k = 714 ____________ (1)

The other airplane is carrying 78 meals and 57 medical kits and the total cost for the supplies on that airplane is $789.

This means that:

78m + 57k = 789 ____________(2)

We now a system containing two linear equations that can be used to solve to problem:

63m + 57k = 714 ____________ (1)

78m + 57k = 789 ____________(2)

To find the price of one meal, we subtract equation (1) from (2) and simplify:

 78m + 57k = 789

<u>- 63m + 57k = 714 </u>_

  15m  = 75

=> m = 75 / 15 = $5

The price of one meal is $5

6 0
3 years ago
Is this right idk but i need work fir it
bija089 [108]

Answer:

The answer is C 5/4

Step-by-step explanation:

When lines are parallel and you know there is a scalar factor, make the ratio by putting the original over the dilation 15:12 or 15/12 this is the ratio and after you need to reduce by dividing by the greatest common factor. 15 and 12's GCF is 3 so (15/3)/(12/3) = 5/4.

7 0
4 years ago
Activity Log - Stretching
Svet_ta [14]

Answer:

here are random times

Step-by-step explanation:

15min

5min

muscular

burpies 5 min

moderate

25mins

8 0
3 years ago
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Convert log_8 1=0 into an exponential equation<br> o 1^0=8<br> O 0^8=1<br> o '8^0=1<br> o '8^=8
Ilia_Sergeevich [38]

Given:

The logarithmic equation is:

\log_81=0

To find:

The exponential equation for the given logarithmic equation.

Solution:

We have,

\log_81=0

It can be rewritten as:

8^{\log_81}=8^{0}

Using a^{\log_ax}=x, we get

1=8^0

8^0=1

Therefore, the correct option is C.

6 0
3 years ago
How do I write 31 / 6 as a mixed number ?
quester [9]
Division. The answer is 5 1/6.
4 0
4 years ago
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