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mezya [45]
3 years ago
10

Pls help to get brainlist

Mathematics
2 answers:
ExtremeBDS [4]3 years ago
7 0

Answer: 15/10-12/10= 3/10

Step-by-step explanation:

Lubov Fominskaja [6]3 years ago
4 0

Answer: Please give brainliest!!!

\frac{3}{2} = \frac{15}{10}

\frac{15}{10} - \frac{12}{10} = \frac{3}{10}

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PlZ HELP 1 + 1 = ?<br> If you play avakin life, drop ur friendcode:
Harrizon [31]

Answer:

2 and I do not play it.

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
If −1 is a zero of the polynomial p(x)=ax^3−x^2+x+4, find the value of a.
vitfil [10]

Answer:

a = 2

Step-by-step explanation:

given x = - 1 is a zero then f(- 1) = 0 , that is

a(- 1)³ - (- 1)² - 1 + 4 = 0

- a - 1 - 1 + 4 = 0

- a + 2 = 0 ( subtract 2 from both sides )

- a = - 2 ( multiply both sides by - 1 )

a = 2

8 0
2 years ago
2 The width of a rectangle is represented by 5 + 2y.
nexus9112 [7]

Answer:

your answer is B 6(5.+2y)

forgive me if i am wrong

3 0
3 years ago
the length of a new rectangle playing field is 6 yards longer than quadruple the width. if the perimeter of the rectangle plaing
Vika [28.1K]

The length and width of a new rectangle playing field are 214 yards and 52 yards respectively.

<h3>What is the area of the rectangle?</h3>

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

We have:

The length of a new rectangle playing field is 6 yards longer than quadruple the width.

Let's suppose the length is l and width is w of a rectangle:

From the problem:

l = 6 + 4w

Perimeter P = 2(l + w)

532 = 2(l + w)

Plug l = 6+4w in the above equation:

532 = 2(6 + 4w + w)

266 = 6 + 5w

260 = 5w

w = 52 yards

l = 6 +4(52) = 214 yards

Thus, the length and width of a new rectangle playing field are 214 yards and 52 yards respectively.

Learn more about the area of rectangle here:

brainly.com/question/15019502

#SPJ1

5 0
2 years ago
Kindly answer this one. Thank you.​
steposvetlana [31]

Answer:

See below.

Step-by-step explanation:

I'm assuming these questions are about the Midline Theorem (segment AL joins the midpoints of the non-parallel sides.

♦  The midline's length is the average of the lengths of the top and bottom parallel sides.

AL=\frac{OR+CE}{2}

Use this equation and substitute values given in each problem, then solve for the missing information.

1. AL = x, CE = 9, OR = 5

x=\frac{9+5}{2}=7

2. AL = <em>m</em> - 4, CE = 15, OR = 17

m-4=\frac{15+17}{2}=16\\\\m-4=16\\\\\\m=20\\\\AL=20-4=16

3. OR = y + 5, AL = 15, CE = 18

15=\frac{(y+5)+18}{2}\\\\15=\frac{y+23}{2}\\\\30=y+23\\\\7=y\\\\OR = 7+5=12

4 0
2 years ago
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