The lateral area of a cylinder is given by:
Area=πrl+2πr^2
radius,r=12 mm
length,l=5*12=60mm
therefore the lateral area will be:
Area=π*12*60
Area=2,261.95 mm^2
The area of the bases will be:
A=2*π*12^2=904.78 mm^s
The lateral area will be:
2,261.95+904.78
=3,166.73
=3167 mm^2
I + 6 = r
4r = s
i + r + s = 126
4i + 24 = 4r
s= 4r
i = r-6
4i+24=i+6
-3i=18
i = 6
Solve the rest
60 mg is equal to .00006 kg
I can’t see it sorry maybe it’s my device
the point of intersection on the graph are (3,-2)