Question

A nut mixture of peanuts and pecans at a small fair is $1.00 per pound of peanuts and $4.25 per pound of pecans. Over the entire day, 115 pounds of the nut mixture was sold for $358.75. If p is the number peanuts and n is the number of pecans, then the system of equations that models this scenario is: p+n=115p+4.25n=358.75 Determine the correct description and amount of pounds for peanuts and pecans that were sold.

Answer 1

Hello!

You can solve this algebraically

p + n = 115

p + 4.25n = 358.75

Subtract the two equations to eliminate p

-3.25n = -243.75

Divide both sides by -3.25

n = 75

Put n into the first equation

p + 75 = 115

Subtract 75 from both sides

p = 40

The answers are,

40 pounds of peanuts were sold
75 pounds of pecans were sold

Hope this helps!