The point-slope form of the equation of a line that passes through points (8, 4) and (0, 2) is

If sec0+tan0=p,then find the value of cosec0.

Ugo [173]

Answer:

Step-by-step explanation:

p=sec0+tan0

=1/cos0 + sin0/cos0

=(1+sin0)/cos0

square both sides

(1+sin)^2 /cos^2 = p^2

(1+sin)^2/(1 - sin^2 ) = p^2

(1+sin)^2/((1-sin)(1+sin)) = p^2

(1+sin)/(1-sin)=p^2

1+sin=p^2-p^sin

sin+p^2sin=p^2-1

sin(1+p^2)=(p^2-1)

sin=(1-p^2)/(1+p^2)

cosec=1/sin

=(1+p^2)/(1-p^2)

6 0

3 years ago

Val has 3/4 gallon of milk. He gives 1/2 of it to a friend. How many gallons of milk does Val have left

Murljashka [212]

Step-by-step explanation:

given, ¾-½= ¼gallon milk.

hope this helps you.

8 0

2 years ago

How can you quickly determine the number of roots a polynomial will have by looking at the equation?

Shtirlitz [24]

One can determine the number of roots by seeing the degree of the given polynomial.

The number of roots can be determined by just seeing the highest power of the given equation.

1) for the equation x-4=0

here, the highest power of the equation is one. So, it will have one root.

<h3>What is the polynomial?</h3>

A polynomial is an expression consisting of indeterminates and coefficients, that involves only the operations of addition, subtract multiplication, on, and non-negative integer exponentiation of variables.

Let's check it by simplifying x-4=0 which implies x=4

Hence, the equation has only one root namely x = 4.

2) Consider a quadratic equation,

10t^2-t-3=0

here, the highest power of the equation is two. So, it will have two roots.

Let's check it by simplifying using the middle term splitting method,

10t^2+5t-6t-3=0

5t(2t+1)-3(2t+1)=0

(5t-3)(2t+1)=0

t=-3/5 or t=-1/2

Thus, the equation has two roots.

Hence, one can determine the number of roots by seeing the degree of the given polynomial.

To learn more about the polynomial visit:

brainly.com/question/2833285

#SPJ1

3 0

1 year ago

The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st

Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

$v=\frac{d}{t}$ .

Applying this to our problem we have that

$v=\frac{200m}{6.509s}= 30.726m/s$ .

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that $v=\frac{d}{t}$ . This formula implies that

$t=\frac{d}{v}$ .

First, observer that $19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s$ .

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, $v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.$

Then, applying 1) we have that

$t=\frac{200m}{36.003m/s}=5.5549s.$

So, Sam Whittingham’s time through the 200 m was 5.5549s.

5 0

3 years ago

Geometry help will give brainliest

blsea [12.9K]

In a parallogram the two angles on the same side ( Angle T and Angle C) equal 180 degrees

So we have 8x +29 + 2x +11 = 180

combine the like terms:
10x + 40 = 180

Subtract 40 from each side:
10x = 140

Divide each side by 10:
X = 140 /10
X = 14

Now we have X, replace X into the equation for angle C

2(14) +11 = 28 + 11 = 39 degrees

6 0

2 years ago

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