p(x)=2x^6+123.5x^4+389x^2−25x^5−304.75x^3−237.25x+53.5
put in decreasing order
p(x)=2x^6−25x^5+123.5x^4−304.75x^3+389x^2−237.25x+53.5.
the leading coefficient is the number in front of the largest exponent
leading coefficient:2
degree is the power on the largest exponent
degree:6
So you would do 555 times 3 1/5. Your answer would be 1776 feet tall.
The question is incomplete. Here is the complete question.
m∠J and m∠Kare base angles of an isosceles trapezoid JKLM.
If m∠J = 18x + 8, and m∠M = 11x + 15 , find m∠K.
A. 1
B. 154
C. 77
D. 26
Answer: B. m∠K = 154
Step-by-step explanation: <u>Isosceles</u> <u>trapezoid</u> is a parallelogram with two parallel sides, called Base, and two non-parallel sides that have the same measure.
Related to internal angles, angles of the base are equal and opposite angles are supplementary.
In trapezoid JKLM, m∠J and m∠M are base angles, so they are equal:
18x + 8 = 11x + 15
7x = 7
x = 1
Now, m∠K is opposite so, they are supplementary, which means their sum results in 180°:
m∠J = 18(1) + 8
m∠J = 26
m∠K + m∠J = 180
m∠K + 26 = 180
m∠K = 154
The angle m∠K is 154°
Answer:
143º
Step-by-step explanation:
You want to find m<HBD
which is m<HBA minus m<BAD
180º minus 37º equals 143º
m<HBD is equal to 143º
Please give me brainliest
Can anyone who sees this answer my latest question?
I need help with it very soon.
Answer:
x+y/4 = 1/2
x-3y/3 = 2
move variables to one side:
multiply the first equation by 4 to get: x+y =2
and the second equation by 3 to get: x-3y =6
then subtract the equations to cancel out x:
x+y = 2
- x-3y = 6
then u get
y--3y = 2-6
4y = -4
y=-1
substitute to solve for x:
x-1 / 4 =1/2
x-1 = 2
x=3
check:
3+-1
2/4= 1/2
correct!!!
