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3 years ago

6. A. y=-13x1 or B. y = 1-3xl

Mathematics

1 answer:

IrinaVladis [17]3 years ago

6 0

Answer: B

Step-by-step explanation

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Raul deposited $3000 into a bank account that earned simple interest each year. After 3.5 years, he had earned $262.50 in intere

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I believe it's 75% but i'm not positive.

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3 years ago

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The number of students in a chess club decreased from 17 to 10. What is

Svetllana [295]

Answer:

41.18%

Step-by-step explanation:

Initial number = 17
Final number = 10

Decrease in number:

17 - 10 = 7

Percent decrease:

7/17*100% = 41.18% (rounded)

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2 years ago

Use the multiplication property of equality to multiply both sides of the equation by 1/6 to get: (1/6)6x=(1/6)48.

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X= 8 because by multiplying the fraction with a whole number you had to to convert it to i a fraction and that equals one and then 1/6 times 48 is 8

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3 years ago

Write the power set of the set A={a,b,c}

Burka [1]

Answer:

P(A) = {{a},{b},{c},{a,b},{a,c},{b,c},{a,b,c},∅}

Step-by-step explanation:

➨ Power Set is the set of all subsets.

First, find the subset of A.

{a},{b},{c},{a,b},{a,c},{b,c},{a,b,c},∅

If you aren't sure that you already have written all subsets or not, use the following formula.

$2^n$ ➩ where n is the number of element/members.

Our number of members are 3, use the following formula.

$2^3=8$

Thus, our subsets should be 8.

As we've already gathered all subsets, write the braces all whole subsets.

P(A) = {{a},{b},{c},{a,b},{a,c},{b,c},{a,b,c},∅}

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3 years ago

Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1

sleet_krkn [62]

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}$

From Left side:

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)$

$\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}$

NOTE: sin²θ + cos²θ = 1

$\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}$

$\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}$

$\dfrac{2sec^2\theta}{tan^2\theta-1}$

Left side = Right side so proof is complete

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3 years ago

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