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Mars2501 [29]
3 years ago
12

How many solutions does the system of equations have?

Mathematics
2 answers:
sertanlavr [38]3 years ago
7 0
Y = 4 x + 3 
<span>y = 4 x + 3/2 
</span>no solution :) hope this helps
Rainbow [258]3 years ago
7 0
<span>
2y-8x=3
2y = 8x -3
y = 4x - 3/2

</span><span>y = 4x + 3
</span>y = 4x - 3/2
---------------subtract
0 = 0 + 4 1/2

0 can not equal 4 1/2

There's no solution


answer is <span>D.none</span>
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Twice last month, Judy Carter rented a car in Fresno, California, and traveled around the Southwest on business. The car rental
ozzi

Answer:

Step-by-step explanation:

Let d = daily fee in dollars

Let +m = milage charge in dollars

In words:

( Cost of rental ) = ( number of days rented )x( daily fee ) + ( miles driven )x( milage fee )

For her first trip:

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For her 2nd trip:

(2) +146+=+3d+%2B+200m+

-------------------------

Multiply both sides of (1) by +3+

Multiply both sides of (2) by +4+,

Then subtract (2) from (1)

4 0
3 years ago
Consider the following division of polynomials.
bonufazy [111]
A) using long division is one way you can divide polynomials. There are other ways (such as synthetic division) but most prefer the long division. You could use mathematical methods, but long division or synthetic division is the best way to go.
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4 years ago
What is the perimeter of the given triangle?
vovikov84 [41]

Answer:

17.2 units

Step-by-step explanation:

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4^2 + 6^2 = sqrt(52)


This would mean that the hypotenuse is 7.211102550927979 units or 7.2 units (the square root of 4^2 + 6^2).


Now you would need to just add all three sides.
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2 years ago
Pauline's cell phone bill is $39.99 a month for a fixed amount of minutes. For any minute she goes over the allowed amount, she
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3 years ago
Read 2 more answers
Plz help i dont understand
Elina [12.6K]
You can search in google if you want for the "inscribed quadrilateral conjecture"

and if you want... I can give you a quick proof of it

hmmm in short, if you inscribe a quadrilateral polygon in a circle
it will have 4 angles

each pair of opposite angles, are "supplementary angles", or they add up to 180°

so.. that said in yours, R+P = 180 and Q+O = 180 as well

you only need Q

so  \bf \measuredangle Q+\measuredangle O=180\qquad &#10;\begin{cases}&#10;\measuredangle Q=2x+4\\\\&#10;\measuredangle O=2x&#10;\end{cases}\implies (2x+4)+(2x)=180

solve for "x"

how big is Q? well, 2x + 4 :)
5 0
4 years ago
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