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Marat540 [252]
3 years ago
9

At one gym, there is a $12 start-up fee, and after that each month, m, at the gym costs $20. At another gym, each month at the g

ym costs $22. After how many months will the cost of both gyms be the same? =
Mathematics
1 answer:
Nutka1998 [239]3 years ago
6 0
6 weeks
Because 132/22=6 and 132-12/20=6
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VashaNatasha [74]
The answer is false they don’t equal each other.
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3 years ago
What is the following product?<br> 3V24•3V45 3V69 4(3V6) 6(3V5) 6(3V10)
lora16 [44]

Answer:

option 3

Step-by-step explanation:

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2 years ago
A car dealership sells 0, 1, or 2 luxury cars on any day. When selling a car, the dealer also tries to persuade the customer to
melisa1 [442]

Answer:

Mean = 1.42

Variance = 0.58

Step-by-step explanation:

Given: X denote the number of luxury cars sold in a given day, and Y denote the number of extended warranties sold.

Also, joint probability function of X and Y are given.

To find:

mean and variance of X

Solution:

From the given joint probability function of X and Y,

P(X=0)=\frac{1}{6}\\P(X=1)=\frac{1}{12}+\frac{1}{6}=\frac{1+2}{12}=\frac{3}{12}\\P(X=2)=\frac{1}{12}+\frac{1}{3}+\frac{1}{6}=\frac{1+4+2}{12}=\frac{7}{12}

Mean of X:

E(X)=\sum XP(X)\\=0\left ( \frac{1}{6} \right )+1\left ( \frac{3}{12} \right )+2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{14}{12}\\=\frac{17}{12}=1.42

Variance of X:

E(X^2)=\sum X^2P(X)\\=0^2\left ( \frac{1}{6} \right )+1^2\left ( \frac{3}{12} \right )+2^2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{28}{12}\\=\frac{31}{12}

var(X)=E\left [ X^2 \right ]-\left ( E\left [ X \right ] \right )^2\\=\frac{31}{12}-\left ( \frac{17}{12} \right )^2\\=\frac{31}{12}-\frac{289}{144}\\=\frac{372-289}{144}\\=\frac{83}{144}\\=0.58

5 0
3 years ago
GCF of 30 48 and 72​
USPshnik [31]
The greatest common factor of those numbers is 8.
7 0
3 years ago
A baseball card bought for $75 increases in value by 3% per year. what is the value of the card after 15 years
sammy [17]
If the value of the baseball card increases by 3% per year then we can say that each year the value of the card may be multiplied by 103% = 1.03, thus:

Value after n years = original price*(1.03)^n
Value after 15 years = 75*(1.03)^15
= $116.85
8 0
3 years ago
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