to write 98 as a product of its prime factors we have to first find the prime factors of 98
prime factors are prime numbers by which the given number can be divided by.
98 we have to keep dividing it by prime numbers
98 is an even number so we can first divide by 2
98 / 2 = 49
49 is a multiple of 7 which too is a prime number so we can divide 49 by 7
49/7 = 7
7 can be divided again by 1
7/7 = 1
98 is divisible by 2 and 7
so 98 written as a product of prime factors is
98 = 2 x 7 x 7
You're almost finished.
(sin/cos) times cos = 0
Look at the left side. You could write it as (sin x cos) / cos = 0
and simply divide numerator and denominator by the cosine (cancel it).
Then what do you have left ? . . . <u>sin(x) = 0</u> Do I need to finish this for you ?
Hey! So you are going to find the coordinates of P and R
P is (4,0) R is (-6,-4)
Then you can plug it into this formula: (x1-x2)^2 + (y1-y2)^2
Using P and R coordinates that’s:
(4- -6)^2 + (0- -4)^2
10^2 + 4^2
100 + 16=
116
Then you are going to find the square root
So 116 square root is 10.8 rounding to the nearest tenth
Hope this helps!
Answer:
2.200 = 2.2 = 2.20 = 2.2000 = 2.20000...I could go on...
Step-by-step explanation:
