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3 years ago

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Point A is located in which quadrant? On a coordinate plane, point A is at (negative 3, 5). Quadrant I Quadrant II Quadrant III

Quadrant IV

2 answers:

Gennadij [26K]3 years ago

5 0

Point a is located in Quadrant 1

sergeinik [125]3 years ago

4 0

Answer:

Quadrant 1 is ur answer WATCH MANGA AND ANIME SHOWS SUCH AS MY HERO ACADEMIA AND SK8 THE INFINITY AND WONDER EGG PRIORITY ETC TY IF U DO

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K=5/9(F+459.67) solve for F in terms of K

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A triangle has sides of lengths 6,8,and 10. Is it a right triangle ?

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3 years ago

What's the number in between numbers -10 and 70?

damaskus [11]

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$80$

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2 years ago

Read 2 more answers

Use the alternative form of the dot product to find u · v.

vodka [1.7K]

Answer:

Step-by-step explanation:

u = 45

v = 30

Angle between them, θ = 5π / 6 = 150°

(a) The formula for the dot product is given by

$\overrightarrow{u}.\overrightarrow{v}= u v Cos\theta$

$\overrightarrow{u}.\overrightarrow{v}= 45 \times 30 \times Cos150$

$\overrightarrow{u}.\overrightarrow{v}= -1169.13$

(b) $\overrightarrow{u}=Cos\frac{\pi }{3}\widehat{i}+Sin\frac{\pi }{3}\widehat{j}$

$\overrightarrow{u}=0.5\widehat{i}+0.866\widehat{j}$

$\overrightarrow{v}=Cos\frac{2\pi }{3}\widehat{i}+Sin\frac{2\pi }{3}\widehat{j}$

$\overrightarrow{v}=-0.707\widehat{i}+0.707\widehat{j}$

Let the angle between them is θ

The formula in terms of the dot product is given by

$Cos\theta =\frac{\overrightarrow{u}.\overrightarrow{v}}{u v}$

$u=\sqrt{0.5^{2}+0.866^{2}}=1$

$v=\sqrt{-0.707^{2}+0.707^{2}}=1$

$Cos\theta =\frac{0.5 \times (-0.707) + 0.866 \times 0.707)}{1\times 1}$

$Cos\theta=0.2587$

θ = 75°

(c) $\overrightarrow{u}=1\widehat{i}+4\widehat{j}+8\widehat{k}$

$u=\sqrt{1^{2}+4^{2}+8^{2}}=9$

$Cos\alpha =\frac{1}{9}$

$Cos\beta =\frac{4}{9}$

$Cos\gamma =\frac{8}{9}$

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3 years ago