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Firdavs [7]
3 years ago
8

What is the faster way for browsers to obtain the revocation status of a digital certificate attached to a Web site?

Computers and Technology
1 answer:
Lyrx [107]3 years ago
5 0

Answer:

The fastest way to obtain the revocation status of digital certificate of the website is by using Online certificate Status Protocol (OSCP).

Explanation:

Online certificate status protocol is the protocol that help user to check and verify the digital certificate revocation status. This protocol is linked with the digital certificate issuance authority. Whenever someone want to verify the status of the digital certificate that is attached to access the website. The website administrator can send the request to OSCP handler to ensure the status of the certificate. The OSCP handler is connected through certificate issuance authority, send the detail to verify the status. After verifying the status, OSCP handler respond as certificate is valid or revoked to the concerned user.

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What is the output of the following function call? //function body int factorial(int n) { int product=0; while(n > 0) { produ
maks197457 [2]

Answer:

zero

Explanation:

Because of the define the product variable is zero.

when the function call with pass by value 4.

The program control moves to that function, after that product

store the value zero. Then, product is multiply with n which become zero

because 0 * n is zero and store in the product again.

after that, n'' is wrong it must be 'n--' for performing the factorial function.

after that, the value of n is 3, again loop execute because condition n > 0

is true.

again zero multiply with n and become zero.

this process repeated until condition false and finally the output is zero.

Correction:

To make the code working:

change product = 1 instead of zero.

and change n-- in place of n''.  

5 0
3 years ago
____ returns the maximum number of elements that can be inserted into the vector container vecCont without reallocation.
Gemiola [76]

Answer:

<u>vecCont.capacity()</u> returns the maximum number of elements that can be inserted into the vector container vecCont without reallocation.

Explanation:

Consider the provided information.

vecCont.capacity() is a function that returns the maximum number of elements(without reallocation) that can be inserted into the container.

<u>vecCont.capacity()</u> returns the maximum number of elements that can be inserted into the vector container vecCont without reallocation.

6 0
3 years ago
What are issues to consider when deciding to build software in-house or purchase commercial off-the-shelf software (cots)?
Scrat [10]
<span>On the computer there are always issues. For a developer to sit all day in front of a google that always invents things and the flashy images that disrupt everything. Googling on facebook is also an issue. Youtube, everything that contain flashy image is quite disruptive. If you think about content, maybe googling is less inventive. In a way it's nicer to buy applications but if you finally think of building it, there are always nicer ways of spending time. I prefer to go to seaside when I can.</span>
7 0
3 years ago
cout &lt;&lt; "Part 1" &lt;&lt; endl; // Part 1 // Enter the statement to print the numbers in index 4 and index 9 // put a spac
Margarita [4]

Answer and Explanation:

#include <iostream>

using namespace std;

int printEven(int array[],int n)

{

int count=0;

for(int i=0;i<n;i++)

{

if(array[i]%2==0)

{

count++;

cout<<array[i]<<" ";

}

}

return count;

}

void printAll(int array[],int n)

{

for(int i=0;i<n;i++)

{

cout<<array[i]<<" ";

}

}

int computeTotalOdds(int array[],int n)

{

int count=0;

for(int i=0;i<n;i++)

{

if(array[i]%2!=0)

{

count++;

 

}

}

return count;

}

int main()

{

int array1[20] = {3, 18, 1, 25, 4, 7, 30, 9, 80, 16, 17};

int numElements = 11;

cout << "Part 1" << endl;

cout<<array1[4]<<" "<<array1[9];

cout << endl;

cout<<array1[0]<<" "<<array1[8];

cout << endl;

array1[2]=12;

cout << "\nPart 2" << endl;

printAll(array1,numElements);

 

cout << "\nPart 3" << endl;

int evens;

evens=printEven(array1,numElements);

 

 

 

 

// This will print the number of evens in the array.

cout << endl << evens;

 

cout << "\nPart 4" << endl;

 

int total;

 

total=computeTotalOdds(array1,numElements);

cout << endl << total;

 

return 0;

}

3 0
2 years ago
WILL GIVEE BRAINLIEST ANSWER!!!!
Licemer1 [7]

Answer:

People have been ringing the death knell for email on and off for a few years now. But should we be listening?

The latest peal came from French IT company Atos, which declared that it would phase out internal emails by 2013. And for reasons we’ll all recongize: too much time spent dealing with too many emails, of which too few are useful and too many are spam. CEO Thierry Breton said his staff would instead use good old face-to-face communication, as well as instant messaging (IM) and social media tools.

3 0
3 years ago
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