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Lisa [10]
3 years ago
11

-2x - 2y + 2z = 16 4x - y - Z = -19 5x + y - 3z = -30

Mathematics
1 answer:
svetlana [45]3 years ago
5 0

Answer: 1. y=-x+z-8

2. y=-Z+4x+19

3. y=-5x+3z-30

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The point slope form of the equation of the line that passes through (-5-1) and (10.-7) is
Natalka [10]

Answer:

The standard form of the equation for this line can be:

l: 2x + 5y = -15.

Step-by-step explanation:

Start by finding the slope of this line.

For a line that goes through the two points (x_0, y_0) and (x_1, y_1),

\displaystyle \text{Slope} = \frac{y_{1} - y_{0}}{x_{1} - x_{0}}.

For this line,

\displaystyle \text{Slope} = \frac{(-1) - (-7)}{(-5) - 10} = -\frac{2}{5}.

Find the slope-point form of this line's equation using

  • \displaystyle \text{Slope} = -\frac{2}{5}, and
  • The point (-5, -1) (using the point (10, -7) should also work.)

The slope-point form of the equation of a line

  • with slope m and
  • point (x_{0}, y_{0})

should be l:\; y - y_{0} = m(x - x_0).

For this line,

  • \displaystyle m = -\frac{2}{5}, and
  • x_0 = -5, and
  • y_0 = -1.

The equation in slope-point form will be

\displaystyle l:\; y - (-1) = -\frac{2}{5}(x - (-5)).

The standard form of the equation of a line in a cartesian plane is

l: \; ax + by = c

where

a, b, and c are integers. a \ge 0.

Multiply both sides of the slope-point form equation of this line by 5:

l:\; 5 y + 5 = -2x -10.

Add (2x-5) to both sides of the equation:

l: \; 2x + 5y = -15.

Therefore, the equation of this line in standard form is l: \; 2x + 5y = -15.

7 0
3 years ago
-1/2x+12=-16 1/2 help<br> Plz I need it quick
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Subtract 12 from both sides
- \frac{1}{2} x+12-12=-16 \frac{1}{2} -12- \frac{1}{2}x=-28 \frac{1}{2}
Divide by -\frac{1}{2} which means multiply by -2
x=-28 \frac{1}{2} *-2=57

Hope that helps

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Answer:s^2-25

Step-by-step explanation:

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